CODEWITHSUNDEEP
c++typedef
Escap3faith
Escap3faith

Reputation: 59

typedef type mismatch passing it into a function

I have a header that has 

typedef double func(double)

and a function declaration in a header called

double function(func f);

This is defined to do something in a corresponding .C file. So, to access this I have a file main.C that contains

#include"necessaryheader.h"

double f(double x){
  return 1.0;
}

int main(){
  func f;
  double x = function(f);
  std::cout << x << std::endl;
}

But when I attempt to compile this it throws an error

undefined reference to `function(double (*)(double))'

Why is this, is that not exactly the type that 'function(func f)' takes as a parameter? A better question is how do I make the types match?

Upvotes: 0

Views: 257

Answers (1)

Remy Lebeau
Remy Lebeau

Reputation: 595961

typedef double func(double)

Should be

typedef double (*func)(double);

And make sure you are linking to a source file that contains the actual implementation of function().

And you need to get rid of the func f; declaration in main().

Upvotes: 1

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