Reputation: 123
I have a highly skewed outcome variable TnI, which I have transformed using log2. I have used the excellent rms package to plot the OLS predictions. Is it possible to exponentiate log2(TnI) to get the plots of predictors vs TnI instead of log2(TnI)? Many thanks, Annemarie
dd <- datadist(df); options(datadist="dd")
m1 <- ols(log2(tni) ~ age + ischaemia, data=df, x=TRUE, y=TRUE)
plot(Predict(m1)
Upvotes: 0
Views: 215
Reputation: 174803
Yes; the inverse of the transformation xx = log_2(x)
is x = 2^xx
. More generally, the inverse of taking logs of x
using base b
is b^x
.
For example:
> x <- c(4,8)
> xx <- log2(x)
> 2^xx
[1] 4 8
For the Predict()
function/method, you'll need to do
predvals <- 2^Predict(m1)$yhat
or something similar, to extract the predicted values from the data frame returned by Predict()
. If there are components lower
and upper
(if you requested a confidence interval) then you can extract and back transform these in the same manner.
Upvotes: 1