CODEWITHSUNDEEP
iosswift3
Luis Ramirez
Luis Ramirez

Reputation: 1604

Delete rest of string after a certain character

I wanted to know how would you delete the rest of a string after a certain character. I know how to replace the occurrences of a string but don't know how would you delete the rest of the string after a certain character. Example

let names = ["Tommy-normal", "Bob-fat", "Jack-skinny", "Rob-obese"]
for x in names {
print(x.replacingOccurrences(of: "-", with: " "))

}

Instead I would like to just delete the rest of the string that comes after - so it will just print out Tommy, Bob, Jack and Rob.

Would appreciate any Help.

Upvotes: 0

Views: 88

Answers (4)

Duncan C
Duncan C

Reputation: 131408

If you want to do it using Sulthan's suggestion (vadian's 2nd approach) but want to make it slightly more general-purpose you could create a function that extracts the first part of a string up to a delimiter, and then use that:

func firstPart(of aString: String, separator: String) -> String {
  if let range = aString.range(of: separator) {
    return aString.substring(to: range.lowerBound)
  }
  return aString
}



let names = ["Tommy", "Bob-fat", "Jack-skinny", "Rob-obese"]
let firstParts: [String] = names.map {
  firstPart(of: $0, separator: "-")
}
print("firstParts = \(firstParts)")

That gives the result:

firstParts = ["Tommy", "Bob", "Jack", "Rob"]

You could also write code that maps your original array into tuples with a name part and a "morphology" part:

let tuples = names
  .map{$0.components(separatedBy: "-")}
  .map{(name:$0[0], morphology: $0.count > 1 ? $0[1] : "unkown morphology")}

tuples.forEach{ print($0.name + " is " + $0.morphology) }

With my version of your data, where I deleted the "-normal" part of "Tommy-normal", to make sure the code handled missing suffixes, I get:

Tommy is unkown morphology
Bob is fat
Jack is skinny
Rob is obese

Upvotes: 0

David Aldana
David Aldana

Reputation: 35

You could try this:

let names = ["Tommy-normal", "Bob-fat", "David", "Jack-skinny", "Rob-obese"];

for (let name of names) {

    let index = name.indexOf("-");

    if (index >= 0) name = name.substring(0, index);

    console.log(name);
}

Be careful when the word starts with "-".

I hope this helps you!

Upvotes: 0

Luke Stanyer
Luke Stanyer

Reputation: 1484

You could split into an array and take the first element as below:

var names = ["Tommy-normal", "Bob-fat", "Jack-skinny", "Rob-obese"]

for name in names {
let arr =  name.components(separatedBy: "-")
        print(arr[0])
}

Prints:

Tommy

Bob

Jack

Rob

Upvotes: 0

vadian
vadian

Reputation: 285069

A possible solution is map with a closure

var names = ["Tommy-normal", "Bob-fat", "Jack-skinny", "Rob-obese"]

names = names.map { string -> String in
    if let range = string.range(of: "-") {
        return string.substring(to: range.lowerBound)
    }
    return string
}

Or

names = names.map { string -> String in
    if let index = string.characters.index(of: "-") {
        return string.substring(to: index)
    }
    return string
}

Upvotes: 2

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