CODEWITHSUNDEEP
pythondictionaryrange
Vaibhav Borkar
Vaibhav Borkar

Reputation: 171

How can I extract data from a dictionary by specifying a range of values?

I have a dictionary, 

{"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"}

I want to extract the data from this dictionary whose values are in the range 20 - 30.

Example. I want the output should be 

apple:20   
banana:25

I was thinking to order the dictionary first by the values, but it does not seem to work.

I tried dict= sorted(dict.items(), key=lambda t: t[1])
but the output shows like this: 

[("apple", "20"), ("orange" , "40"), ("banana" , "25"), ("mango" , "50")]

How can I get output as: 

apple:20   
banana:25

Upvotes: 2

Views: 2691

Answers (7)

martineau
martineau

Reputation: 123491

You could use a set to obtain fast membership testing. Doing so also eliminates the need to convert the dictionary's values to integers since the members of the set are strings:

d = {"apple": "20", "orange": "40", "banana": "25", "mango": "50"}
limits = set(str(n) for n in range(20, 31))

for key, value in sorted(d.items()):
    if value in limits:
        print('{}:{}'.format(key, value))

Upvotes: 0

Pitu
Pitu

Reputation: 51

Returns a dict {'apple': '20', 'banana': '25'}

>>> d = {"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"} >>> {key: val for key,val in d.items() if 20 <= int(val) <= 30} {'apple': '20', 'banana': '25'}

Upvotes: 0

user2390182
user2390182

Reputation: 73470

You can do the following:

> d = {"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"}
> for item in sorted(d.items(), key=lambda i: int(i[1])):
>   print ': '.join(item)
apple: 20
banana: 25
orange: 40
mango: 50

sorted sorts the dict's items (which are key-value tuples) by the value using a a specific sorting key.

Upvotes: 3

Ajax1234
Ajax1234

Reputation: 71461

Using dictionary comprehension:

the_dict = {"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"}

new_dict = {the_dict.keys()[i]:the_dict.values()[i] for i in range(len(the_dict.values())) if int(the_dict.values()[i]) <= 30 and    int(the_dict.values()[i] >= 20)}

print new_dict

Upvotes: 0

ᴀʀᴍᴀɴ
ᴀʀᴍᴀɴ

Reputation: 4528

With using of list comprehension you can extract (key,values) that their values (first cast to int) are in range 20-30 :

d = {"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"}
[(k,v) for k,v in d.items() if  20 <= int(v) <= 30]
# [('banana', '25'), ('apple', '20')]

Then you can have your desired output.

Upvotes: 1

Terry Jan Reedy
Terry Jan Reedy

Reputation: 19174

d = {"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"}

for k, v in d.items():
    if 20 <= int(v) <= 30:
        print(k, ':', v, sep='')

prints

apple:20
banana:25

Upvotes: 1

Mia
Mia

Reputation: 2676

sample_dict={"apple" : "20", "orange" : "40", "banana" : "25", "mango" : "50"}
for name,num in sample_dict.items():
    if int(num) in range(20,31):
        print('%s: %s' %(name,num))

Upvotes: 2

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