CODEWITHSUNDEEP
phpdate
Karthick Sri
Karthick Sri

Reputation: 41

how to get each month last date in php, year will change according to cuurent date

i want to get each month last date for every year. year will change and it should take from currdate.

i tried below one

$day = date( 't-m-Y' );

But am writing different if condition for each month. So in this code i want to give constant month. year will change. Is it possible to do like that?

can anyone help me to do this.

Upvotes: 1

Views: 248

Answers (5)

slevy1
slevy1

Reputation: 3832

The last date of the month stays the same year in and year out, i.e. December will have 31 days whether referencing this year or the next. The only thing that changes is on what day of the week the last day of a month falls. So, the following indicates how to obtain all this data for the current month and the remaining months of the year as well as for next year. 

<?php

// preliminaries
try {
    $date =  new DateTime("@".time());
} catch (Exception $e) {
    echo $e->getMessage();
    exit(1);
}

$strDate = $date->format("Y-n-t");
list($Y,$m,$t)  =  explode("-",$strDate);
$offset = 12 - $m;
$max = $offset + 1; // include current month


//this year starting with current month:
for ( $i=0; $i < $max; $i++ ){
    $mo_day_one_yr = "$Y-" . ( $m + $i ) . "-1";
    $date->modify( $mo_day_one_yr );
    echo $date->format("D, t-M-Y"),"\n";
    if( $i == ( $max -1 )) echo "\n";
}


// next year:
for ( $i=1, $Y+=1, $max=12; $i <= $max; $i++ ){
    $mo_day_one_yr = "$Y-$i-1";
    $date->modify( $mo_day_one_yr );
    echo $date->format("D, t-M-Y"),"\n";
}

Live code

Note, the DateTime object gets initialized with a Unix timestamp string but one could also just simply provide a parameter of "now". Also, the try-catch is a good idea just in case an issue should arise in terms of instantiating the DateTime object.

Upvotes: 0

Shafiqul Islam
Shafiqul Islam

Reputation: 5690

you can check this code

$a_date = "2017-04-17";
echo date("Y-m-t", strtotime($a_date));

or use 

$current_date = "2017-04-17";
$date = new DateTime($current_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');


echo $first_date = date('Y-m-d',strtotime('first day of this month'));
echo $last_date = date('Y-m-d',strtotime('last day of this month'));

this is your code

echo $last_date = date('t-03-Y');

and this is output

30-03-2017

Upvotes: 0

JYoThI
JYoThI

Reputation: 12085

t returns the number of days in the month of a given date

so you can pass the dynamic year and constant month like this to know the last day of month

<?php

 $year ="2017";
 echo date("Y-m-t", strtotime(date("$year-04-d")));

?>

OUTPUT:

2017-04-30

update 1:

 $date = new DateTime('last day of 2017-04');

 echo $date->format('Y-m-d');

Upvotes: 0

Waseem Ahmad
Waseem Ahmad

Reputation: 303

// get Current Date 
$date = date('j-m-Y'); 
echo date("j-m-y", strtotime($date));//Current Month date with Current year
echo "Current Year =".date("Y", strtotime($date))." , Current Month Days =".date("t", strtotime($date))." , Current Month Last Day Date  =".date("t-m-Y", strtotime($date));

Upvotes: 0

LF-DevJourney
LF-DevJourney

Reputation: 28529

Check demo here.

<?php
$year = date("Y");
echo $year . "\n";
for ($i = 1; $i <= 12; $i++)
{
    $month = strtotime("$year-$i");
    echo date("t", $month) . "\n";
}

output:

2017
31
28
31
30
31
30
31
31
30
31
30
31

Upvotes: 1

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