CODEWITHSUNDEEP
java
Badman
Badman

Reputation: 417

How to get desired data from a String efficiently in java?

I have a String Text . I want to get value of "signature" keyword in Text.
Here is my code with example:

public void parseMethod(){
String Text = "hmac username=\"dhannan\", algorithm=\"hmac-sha1\", headers=\"content\", signature=\"VwjwFaNSw3cLQbuqtwl2XPOmcis=\"";
Pattern pattern = Pattern.compile("signature=\"(.+)\"");
Matcher matcher = pattern.matcher(authorization);
int s = Text.indexOf("signature=");
String data="";
int index=s+11;
while(Text.charAt(index)!='"'){
     data+=Text.charAt(index);
     index+=1;
   }
System.out.println(data);
}

So this will give me output that I want :

VwjwFaNSw3cLQbuqtwl2XPOmcis=

I don't like this method. I want to do in simple like regex or something other way.

By using regex way

Pattern pattern = Pattern.compile("signature=\"(.+)\"");
Matcher matcher = pattern.matcher(Text);
if(matcher.find()){
            System.out.println(matcher.group());
}

But it gives this output while I want only value for which I will have to extra work like above:

signature="VwjwFaNSw3cLQbuqtwl2XPOmcis="

Please suggest me an efficient way to do this.

Upvotes: 1

Views: 72

Answers (1)

Jacob G.
Jacob G.

Reputation: 29710

Like 11thdimension suggested, you should use matcher.group(1) to find the value itself:

String Text = "hmac username=\"dhannan\", algorithm=\"hmac-sha1\", headers=\"content\", signature=\"VwjwFaNSw3cLQbuqtwl2XPOmcis=\"";

Pattern pattern = Pattern.compile("signature=\"(.+)\"");

Matcher matcher = pattern.matcher(Text);

if (matcher.find()) {
    System.out.println(matcher.group(1));
}

>> VwjwFaNSw3cLQbuqtwl2XPOmcis=

Upvotes: 1

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