Reputation: 974
Please see below the example for condition_variable
taken from cppreference. In this example, a bunch of threads are waiting for the variable i
to become i == 1
. I took the example and just added a std::this_thread::sleep_for(std::chrono::seconds(1));
instruction inside the workers to check if they were actually running in parallel. To my surprise they don't, so there must be something I am not understanding. Shouldn't all the threads start at the same time once they are notified?
If I remove all the instructions related to condition_variable
, then the threads do run in parallel as expected, so I believe that my compiler (LLVM with C++11 libraries) is compiling correctly.
#include <iostream>
#include <condition_variable>
#include <thread>
#include <chrono>
std::condition_variable cv;
std::mutex cv_m;
int i = 0;
void waits()
{
std::unique_lock<std::mutex> lk(cv_m);
std::cerr << "Waiting... \n";
cv.wait(lk, []{return i == 1;});
std::cerr << "...finished waiting. i == 1\n";
std::this_thread::sleep_for(std::chrono::seconds(1));
std::cerr << "...finished running.\n";
}
void signals()
{
std::this_thread::sleep_for(std::chrono::seconds(1));
{
std::lock_guard<std::mutex> lk(cv_m);
std::cerr << "Notifying...\n";
}
cv.notify_all();
std::this_thread::sleep_for(std::chrono::seconds(1));
{
std::lock_guard<std::mutex> lk(cv_m);
i = 1;
std::cerr << "Notifying again...\n";
}
cv.notify_all();
}
int main()
{
std::thread t1(waits), t2(waits), t3(waits), t4(signals);
t1.join();
t2.join();
t3.join();
t4.join();
}
Upvotes: 1
Views: 541
Reputation: 37513
it looks like they are running in parallel, however only one of them will be able to lock cv_m
mutex after notification and the rest will just wait further.
Upvotes: 3