CODEWITHSUNDEEP
swift
Gobi Manickam
Gobi Manickam

Reputation: 3267

Convert [UInt8] to [UInt32] in Swift 3

How to Convert [UInt8] to [UInt32] in Swift 3?

let u8: [UInt8] = [0x02, 0x02, 0x02]

Upvotes: 1

Views: 2417

Answers (2)

Okan T.
Okan T.

Reputation: 78

I used bit shifting.You can try below code lines.

let bytes: [UInt8] = [41, 22, 91, 13, 85, 71, 12, 34]
func getU32Array(byteArr: [UInt8]) -> [UInt32]? {

let numBytes = byteArr.count
var byteArrSlice = byteArr[0..<numBytes]

guard numBytes % 4 == 0 else { print ("There is not a multiple of 4") ;return nil }

var arr =  [UInt32](repeating: 0, count: numBytes/4)
for i in (0..<numBytes/4).reversed() {
    arr[i] = UInt32(byteArrSlice.removeLast())  + UInt32(byteArrSlice.removeLast()) << 8 + UInt32(byteArrSlice.removeLast()) << 16 + UInt32(byteArrSlice.removeLast()) << 24
}
return arr
} 
print(getU32Array(byteArr: bytes)!)

//output: [689330957, 1430719522]

Upvotes: 1

RajeshKumar R
RajeshKumar R

Reputation: 15748

Try this

let u8: [UInt8] = [0x02, 0x02, 0x02]
let u32: [UInt32] = u8.map { UInt32($0)  }
print("u32: \(u32)")

Upvotes: 5

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