Reputation: 409
I have let's say 100 variables in a string , my requirement is to automatically create a Map
out of the string:
String str = "$$test$$ $$test2$$ $$test$$ $$test3$$"
Expected Result:
["test":test, "test2":test2, "test3":test3];
EDIT (for dsharew) This is the last version of my code
def list = queryText.findAll(/\$\$(.*?)\$\$/)
def map = [:]
list.each{
log.debug(it)
it = it.replace("\$\$", "")
log.debug(it)
map.putAt(it, it)
}
log.debug(list)
log.debug(map)
queryText = queryText.replaceAll(/\$\$(.*?)\$\$/) { k -> map[k[1]] ?: k[0] }
log.debug(queryText)
And the logs print the following result:
$$test$$
test
$$test2$$
test2
$$test$$
test
$$test3$$
test3
[$$test$$, $$test2$$, $$test$$, $$test3$$]
{test=test, test2=test2, test3=test3}
test test2 test test3
Upvotes: 0
Views: 89
Reputation: 101
Following @dsharew answer, I've reduced it a little bit more:
def queryText = "\$\$test\$\$ \$\$test2\$\$ \$\$test\$\$ \$\$test3\$\$"
def resultMap = queryText
.findAll(/\$\$(.*?)\$\$/)
.collectEntries { String next ->
[next.replace("\$\$", "")] * 2
}
collectEntries
can be used to return a map from a collection if it returns a map or a tuple for every entry in the collection.
If you multiply a list by n
, you are creating a bigger list with n
times its content
BTW cool problem!
Upvotes: 1
Reputation: 1705
This is what I came up with
String str = '$$test$$ $$test2$$ $$test$$ $$test3$$'
str.replaceAll('\\$\\$', '').split(' ').collectEntries { [(it):it] }
Upvotes: 0
Reputation: 10665
This should do what you want:
def queryText = "\$\$test\$\$ \$\$test2\$\$ \$\$test\$\$ \$\$test3\$\$"
toMap(queryText.findAll(/\$\$(.*?)\$\$/));
def toMap(list){
def map = [:]
list.each{
it = it.replace("\$\$", "")
map.putAt(it, it)
};
println map;
return map;
}
Upvotes: 1