CODEWITHSUNDEEP
pythondjangodjango-urls
Tango
Tango

Reputation: 123

how to write urls.py in django 1.10

urls.py file which is in 1.1 version of Django :-

 urlpatterns = patterns('ecomstore.catalog.views',
    (r'^category/(?P<category_slug>[-\w]+)/$','show_category',
        {'template_name':'catalog/category.html'},'catalog_category'),
 )

which I understood that first argument id prefix to all views. next argument is url which has four argument one is url string(regex),second is view , third is dict passing template name and fourth is location of category.

How to write it in Django 1.10 is following it correct way:-

from django.conf.urls import url
from ecommstore.catalog.views import *
urlpatterns = [
url(r'^category/(?P<category_slug>[-\w]+)/$','show_category',
        {'template_name':'catalog/category.html'},'catalog_category'),
 ]

Upvotes: 0

Views: 334

Answers (1)

knbk
knbk

Reputation: 53699

You're almost there. You've imported the view, but you're still passing in a string as the view instead of the view function itself:

urlpatterns = [
    url(r'^category/(?P<category_slug>[-\w]+)/$', show_category,
        {'template_name':'catalog/category.html'}, 'catalog_category'),
]

Upvotes: 1

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