CODEWITHSUNDEEP
pythonpython-3.xintegerhex
tulians
tulians

Reputation: 448

Hex to integer when reading MIDI file

This might be a simple question. I'm reading a binary MIDI file using Python 3 and I'm having problems understanding how to turn the hex value \x00\x00\x00\x06 into an integer, as I don't know what to do with the slash \. To get this value I'm using:

with open("/path/to/midi/file.mid", "rb") as f:
    header_chunk = f.read(4)
    length = f.read(4)

length ends up having a bytes object with value b"\x00\x00\x00\x06". This value can be the unpacked into the corresponding numbers using struct.unpack("cccc", length) but this returns a tuple with hexadecimal numbers containing the \, (b'\x00', b'\x00', b'\x00', b'\x06'). Is there a built-in way to turn this numbers as they are, in bulk like in length or in an individual fashion, to integers without having to deal with the \ manually?

Upvotes: 2

Views: 292

Answers (1)

juanpa.arrivillaga
juanpa.arrivillaga

Reputation: 95957

Yeah, sure:

>>> length
b'\x00\x00\x00\x06'
>>> list(length)
[0, 0, 0, 6]

Note, if you access the individual elements of your bytes object, you get an int in return:

>>> length[0]
0
>>> length[1]
0
>>> length[2]
0
>>> length[3]
6
>>>

Upvotes: 1

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