Reputation: 21914
I have what I assumed would be a super basic problem, but I'm unable to find a solution. The short is that I have a column in a csv
that is a list of numbers. This csv
that was generated by pandas
with to_csv
. When trying to read it back in with read_csv
it automatically converts this list of numbers into a string
.
When then trying to use it I obviously get errors. When I try using the to_numeric
function I get errors as well because it is a list, not a single number.
Is there any way to solve this? Posting code below for form, but probably not extremely helpful:
def write_func(dataset):
features = featurize_list(dataset[column]) # Returns numpy array
new_dataset = dataset.copy() # Don't want to modify the underlying dataframe
new_dataset['Text'] = features
new_dataset.rename(columns={'Text': 'Features'}, inplace=True)
write(new_dataset, dataset_name)
def write(new_dataset, dataset_name):
dump_location = feature_set_location(dataset_name, self)
featurized_dataset.to_csv(dump_location)
def read_func(read_location):
df = pd.read_csv(read_location)
df['Features'] = df['Features'].apply(pd.to_numeric)
The Features
column is the one in question. When I attempt to run the apply
currently in read_func I get this error:
ValueError: Unable to parse string "[0.019636873200000002, 0.10695576670000001,...]" at position 0
I can't be the first person to run into this issue, is there some way to handle this at read/write time?
Upvotes: 2
Views: 3654
Reputation: 118
I have modified your last function a bit and it works fine.
def read_func(read_location):
df = pd.read_csv(read_location)
df['Features'] = df['Features'].apply(lambda x : pd.to_numeric(x))
Upvotes: 1
Reputation: 294218
You want to use literal_eval
as a converter
passed to pd.read_csv
. Below is an example of how that works.
from ast import literal_eval
form io import StringIO
import pandas as pd
txt = """col1|col2
a|[1,2,3]
b|[4,5,6]"""
df = pd.read_csv(StringIO(txt), sep='|', converters=dict(col2=literal_eval))
print(df)
col1 col2
0 a [1, 2, 3]
1 b [4, 5, 6]
Upvotes: 2