CODEWITHSUNDEEP
shell
Nilan
Nilan

Reputation: 115

Shell cut grep command

req=`bxp report change-summary $startDate $startDate  -iad -y | grep -A2 "Request ID"

The above script gives the below output

Request ID ------------ 10481066

I want to cut only the number 10481066, I tried with number grep and other cut which is not working. Can anyone suggest?

Upvotes: 0

Views: 393

Answers (4)

delete
delete

Reputation: 1

I would do manipulating the final string,

req="Request ID ------------ 10481066"
result=${req%-*}

Upvotes: 0

Nilan
Nilan

Reputation: 115

i just did this way

req=bxp report change-summary $startDate $startDate -iad -y | grep -A2 "Request ID" | grep -E "^[0-9]"

any way thanks for your help

Upvotes: 0

George Vasiliou
George Vasiliou

Reputation: 6335

Just some alternatives to awk:

$ egrep -o '[0-9]+' <<<"This is a line with Request ID ------------ 10481066"
$ cut -d' ' -f4 <<<"Request ID ------------ 10481066"
$ egrep -o '[0-9]+$' <<<"This is a line with number 35546 with Request ID ------------ 10481066"

All above return 10481066

PS: Cut default delimiter is tab, you need to declare with -d option space as delimiter in order cut to work with your data.

Upvotes: 0

anubhava
anubhava

Reputation: 785098

Assuming your output Request ID ------------ 10481066 is all in a single line, you can just replace grep with this awk command:

req=$(bxp report change-summary $startDate $startDate -iad -y|awk '/Request ID/{print $NF}')

Upvotes: 1

Related Questions