CODEWITHSUNDEEP
pythonpython-3.xdivisionmodulus
jay
jay

Reputation: 27

Mod remainder: if num is within 2 of a multiple of 10

I have to write a function to find if a given number (num) within 2 of a multiple of 10. I use modulus (%) to get the remainder, but it doesn't seem to be working quite right. Help?

def nearten(num):
    if num%10<=2:
        return True
    elif num%10>2:
        return False

Upvotes: 0

Views: 4965

Answers (7)

drunkenwhaler_136
drunkenwhaler_136

Reputation: 21

This method also works, just returning a bool value by using comparison operators in a single line to check both 'sides' of the cases:

def near_ten(num):
  return (num % 10 <= 2 or num % 10 >= 8)

Upvotes: 0

moumita das
moumita das

Reputation: 67

This works:

def near_ten(num):
    return num%10 <= 2 or num%10 >= (10 - 2 )

Upvotes: 1

AKHIL_ADARSH
AKHIL_ADARSH

Reputation: 19

Here is a little help:

def near_ten(num):
    return num % 10 in [0,1,2,8,9,10]`

can also be: 

return 0 <= (num % 10) <= 2 or 8 <= (num % 10) <= 10

Upvotes: 1

Vivek Mishra
Vivek Mishra

Reputation: 21

You can use Ternary operator and check for if num is within 2 of multiple of 10:

def near_ten(num):
  return True if num%10<3 or num%10>7 else False

Upvotes: 2

Hafeez Poladzade
Hafeez Poladzade

Reputation: 19

You can write this code as:

def near_ten(num):    
    a = num % 10      
    return 2 >= a or 8 <= a

Upvotes: 1

Shan Gao
Shan Gao

Reputation: 11

def near_ten(num):
     if num%10<=2 :
         return True
     elif num%10 >=8:
         return True
     else:
         return False

Upvotes: -1

Prune
Prune

Reputation: 77837

Most of all, you only checked to see whether the "ones" digit is 0, 1, or 2 -- you missed 8 and 9.

As a styling note, don't check a boolean expression and then hard-code the result you just found. Your function, as currently written, reduces to this:

def nearten(num):
    return num%10 <= 2

Do you see how that works? First of all, the elif check doesn't give you any new information: you already know that the result must be >2 when you get past the if condition.

Then, your statement reads like

if this condition is true, return true
otherwise, we know it's false; return false.

That's redundant. You have a True/False value sitting right in your program's hand -- just return that one, instead of using a constant.

REPAIR ...

I'll leave this as an exercise for the student: "within" 2 means that you have to check both sides, so you have to pick up the cases where the ones digit is 8 or 9. Can you write the expression to do that?

Upvotes: 2

Related Questions