Reputation: 365
I have this:
<div> 16</div>
and I want this:
<div><span>16</span></div>
Currently, this is the only way I can make it work:
preg_replace("/(\D)(16)(\D)/", "$1<span>$2</span>$3", "<div> 16</div>")
If I leave off the $3, I get:
<div><span>16</span>/div>
Upvotes: 0
Views: 1044
Reputation: 365
This is what ended up working the best:
preg_replace('/(<.*>)\s*('. $page . ')\s*(<.*>)/i', "$1" . '<span class="curPage">' . "$2" . '</span>' . "$3", $pagination)
What I found was that I didn't know for sure what tags would precede or follow the page number.
Upvotes: 0
Reputation: 4014
Try following -
$str = "<div class=\"number\"> 16</div>";
$formatted_str = preg_replace("/(<div\b[^>]*>)(.*?)<\/div>/i", "$1<span>$2</span></div>", $s);
echo $formatted_str;
Upvotes: 1
Reputation: 2764
Not quite sure what your after, but the following is more generic:
$value = "<div> 16 </div>";
echo(preg_replace('%(<(\D+)[^>]*>)\s*([^\s]*)\s*(</\2>)%', '\1<span>\3</span>\4', $value));
Which would result in:
<div><span>16</span></div>
Even if the value were:
<p> 16 </div>
It would result in:
<p><span>16</span></p>
Upvotes: 3
Reputation: 138357
I think you meant to say you're using the following:
print preg_replace("/(\\D+)(16)(\\D+)/", "$1<span>$2</span>$3", "<div>16</div>");
There's nothing wrong with that. $3 is going to contain everything matched in the second (\D+) group. If you leave it off, obviously it's not going to magically appear.
Note that your code in the question had some errors:
\
's in a string.\D+
to match multiple characters.\s*
to match any number of whitespace characters.Upvotes: 2