CODEWITHSUNDEEP
pythonlist
Artem Dumanov
Artem Dumanov

Reputation: 423

How to pass each sublist in a nested list as seperate parameter

I have a nested list:

lists = [['q','w','e'],['r','t','y'],['u','i','o']]

And a function:

def func(*iterables)

How call func with my list? I tried:

func(item for item in lists)

But it doesn't work.

Upvotes: 1

Views: 1309

Answers (3)

MSeifert
MSeifert

Reputation: 152667

The item for item in lists is a generator expression, it's still just "one" parameter. You actually need to unpack your lists.

Besides using unpacking (*):

func(*lists)

you could also use a decorator to "utilize" this approach (if you need it often):

def packed(func):
    def inner(args):
        return func(*args)
    return inner

packed(func)(lists)

I recently added such a "decorator" to a package of mine iteration_utilities.packed:

from iteration_utilities import packed

packed(func)(lists)

Upvotes: 1

bamdan
bamdan

Reputation: 856

List comprehension must be in square parenthesis so the syntax is not correct.

func(*lists)

*lists unpacks the list contents so items are separate arguments in your function.

Upvotes: -1

m0dem
m0dem

Reputation: 1008

If I am understanding you correctly...

func(*lists)

This basically unzips the list so the contents can be used as parameters for a function.

The * operator is called a "splat" in some other languages. :)

Upvotes: 2

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