CODEWITHSUNDEEP
phpcsvfopen
oliverbj
oliverbj

Reputation: 6052

PHP - Grab file from folder, only part of name

I have a folder called /attachments, where I store one csv file. However, that csv file is added dynamically, and therefore I don't know it's exact name. I only know that it will always be a .csv file that will start with "stocklist" (for example: stocklist2141.csv or stocklist8281.csv)

How can I "grab" that file using PHP? Right now, I've only been able to find a function for opening a file, where you know the filename:

$filepath = "./includes/api/inventory/attachment/test.csv";
$file = fopen($filepath, "r");

Upvotes: 0

Views: 380

Answers (3)

Sander
Sander

Reputation: 388

As mentioned in a comment, use glob.

The following example retrieves the files with extension .csv in the folder ./files:

//Get all CSV files in folder
$files = glob("./files/*.csv");

foreach($files as $file) {
    //Do interesting stuff with the file.
}

Upvotes: 1

Ahmed Ginani
Ahmed Ginani

Reputation: 6650

$dir = "./includes/api/inventory/attachment/";
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
    if ($dh = opendir($dir)) {
        while (($file = readdir($dh)) !== false) {
            echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
        }
        closedir($dh);
    }
}

Upvotes: 0

junkfoodjunkie
junkfoodjunkie

Reputation: 3178

Something like this should work:

$files = scandir("./includes/api/inventory/attachment");
if (!empty($files)) {
  foreach ($files as $file) {
    // do stuff with $file
  }
}

Upvotes: 0

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