DPP
DPP

Reputation: 59

Get version code of the latest app from playstore programmatically in case of multiple apks

I am facing an issue in fetching the latest version code of my app from the playstore. I have app apk as well as wear apk uploaded on the playstore. Now when I call playstore to get the latest version of the mobile app available, if provide response as:

It varies according to the device

So is there any way to get the the latest version code of the mobile app?

Below is the code I am using to retrieve the latest version code of the app.

private class GetVersionCode extends AsyncTask<Void, String, String> {
    @Override
    protected String doInBackground(Void... voids) {
        String newVersion = null;
        try {
            newVersion = Jsoup.connect("https://play.google.com/store/apps/details?id=" + getApplicationContext().getPackageName() + "&hl=it").timeout(30000)
                    .userAgent("Mozilla/5.0 (Windows; U; WindowsNT 5.1; en-US; rv1.8.1.6) Gecko/20070725 Firefox/2.0.0.6").referrer("http://www.google.com")
                    .get()
                    .select("div[itemprop=softwareVersion]")
                    .first()
                    .ownText();
            return newVersion;
        } catch (Exception e) {
            return null;
        }
    }

    @Override
    protected void onPostExecute(String onlineVersion) {
        super.onPostExecute(onlineVersion);
        if (onlineVersion != null && !onlineVersion.isEmpty()) {
            String currentVer = getIntVersionNumber(currentVersion);
            String onlineVer = getIntVersionNumber(onlineVersion);
            if (Integer.parseInt(currentVer) < Integer.parseInt(onlineVer)) {
                showAlertDialog(onlineVersion);
            }
        }
    }
}

Upvotes: 2

Views: 1410

Answers (1)

Bhupat Bheda
Bhupat Bheda

Reputation: 1978

you get "Varies with device" because application run a different version on devices

enter image description here

if there is version number then you can get version number otherwise not possible

Upvotes: 1

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