CODEWITHSUNDEEP
resthttpgobackendgorilla
Andy Morgan
Andy Morgan

Reputation: 93

Why is GorillaMux not allowing me to pass in a URL as a parameter?

I'm building a URL shortener API and I'm trying to pass a URL into a function using GorillaMux. The route handler is like so:

router.HandleFunc("/new/{url}", createURL)

The only thing is, if I pass in: https://www.google.com (as in localhost:8080/new/https://www.google.com) then it responds with 404 page not found and the URL is changed to https:/www.google.com.

I've tried adding a regexp pattern in with the {url} bit like so: {url:[a-zA-Z0-9/]+} but that didn't seem to work and seems a bit overkill since I'm checking the url is correct elsewhere.

Upvotes: 0

Views: 560

Answers (1)

zerkms
zerkms

Reputation: 254886

You need to encode it so that the slash in the parameter was not confused as a part of the url:

localhost:8080/new/https%3A%2F%2Fwww.google.com

Upvotes: 3

Related Questions