CODEWITHSUNDEEP
python
Martin Bergeron
Martin Bergeron

Reputation: 129

Not returning the right value of the dictionary

i am pretty new to dictionaries and i have a problem with this code. I don't understand why its always outpuing the value 0. it's like if anything i enter goes into this else. The only reason it should display 0 is if the word is missing from the list

if item in resultat.keys():
    print(item, ": {}".format(resultat[item]))
else:
    print(item, ": 0")

Exemple of the dictionnary i am using that is imported from a txt file:

pommes : 54
bananes
oranges : 30

Exemple of input

item.py data1.txt pommes

Exemple of erroneous output i am getting:

pommes : 0

exptected output

pommes : 54

This is my code im working on.

import sys

def ligne(texte, item):
    try:
        with open(texte) as ouvrir:
            mots_dict = {}
            lecture = ouvrir.readlines()
            for line in lecture:
                line = line.strip('\n')
                try:
                    mot, nombre = line.split(':')[1], int(line.split(':')[2])
                except IndexError:
                    continue
                if mot not in mots_dict.keys():
                    mots_dict[mot] = nombre
                elif mot == item:
                    raise Exception('La ligne {} est un doublon.'.format(line))
            return mots_dict
    except IOError:
        print("Le fichier", texte, "n'existe pas.")
        sys.exit()

Upvotes: 2

Views: 418

Answers (1)

Jérémy Lefebvre
Jérémy Lefebvre

Reputation: 74

Try to split with 

' : '

not 

':'

Because if you split just with ':' your code will still keep the space after the word and before the number

Upvotes: 2

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