CODEWITHSUNDEEP
javastringif-statement
Tisco
Tisco

Reputation: 53

How to use 'if' to condition and ignore a word in a particular sentence?

How can I construct a condition that if a phrase has the name "x", then "x" is ignored when the phrase is displayed?

Example:

if(item.contains("Text"))
{
    //Then ignore "Text" and display the remaining mill
}

Upvotes: 4

Views: 1917

Answers (4)

Shivam Sharma
Shivam Sharma

Reputation: 1045

here, replace() can be used. public String replace(char oldChar, char newChar)

Parameters:

oldChar : old character

newChar : new character

public class ReplaceExample1{  
    public static void main(String args[]){  
        String s1="stackoverflow is a very good website";  
        String replaceString=s1.replace('a','e');//replaces all occurrences of 'a' to 'e'  
        System.out.println(replaceString);  
    }
}

O/P:

steckoverflow is e very good website

Upvotes: 4

Zzrot
Zzrot

Reputation: 324

Not the best way, but off the top of my head:

    String x = "This is Text";
    String[] words;
    String newX = "";

    words = x.split(" ");
    for(int i = 0; i < words.length; i++) {
            if(!words[i].equals("Text"))
                newX = newX + " " + words[i];
    }

    System.out.println(newX);

Upvotes: 2

ΦXocę 웃 Пepe&#250;pa ツ
ΦXocę 웃 Пepe&#250;pa ツ

Reputation: 48258

You can use the indexOf() method combined with a ternary operator

String val = "How can I construct a condition that if a phrase ";
String valFinal = val.indexOf("that") != -1 ? val.replace("that", "") : val;
System.out.println(valFinal);

Upvotes: 3

Youcef LAIDANI
Youcef LAIDANI

Reputation: 59950

You can easily use :

String item = "This is just a Text";
if (item.contains("Text")) {
    System.out.println(item.replace("Text", ""));
}

Upvotes: 6

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