CODEWITHSUNDEEP
arraysrubysumintegeraddition
Salam.MSaif
Salam.MSaif

Reputation: 219

Trying to sum from array

    a = gets.split(" ").each {|n| n.to_i}
    puts "#{a[0] + a[1]}"

Say I input 1 2 into the above code. The output will be 12. How to do a simple addition with this code? For the output to be 3

Upvotes: 3

Views: 80

Answers (4)

aqfaridi
aqfaridi

Reputation: 739

one-liner using Enumberable#map and Enumberable#reduce

gets.split.map(&:to_i).reduce(:+)

Upvotes: 0

Cary Swoveland
Cary Swoveland

Reputation: 110685

Suppose gets returns

s = "21 14     7"

Then use Array#sum (new in Ruby v.2.4.0):

puts s.split.sum(&:to_i)
42

or use Enumerable#reduce (aka inject, available since the dawn of time)

puts s.split.reduce(0) { |t,ss| t+ss.to_i }
42

Upvotes: 2

Engr. Hasanuzzaman Sumon
Engr. Hasanuzzaman Sumon

Reputation: 2183

Though accepted answer is correct but only for array with two elements(even for array with 1 element it will break). What if array size is variable? Ruby has more generic ways to do it.

You can use either reduce or inject method documentation

example code:

a = gets.split(" ").map! {|n| n.to_i}
puts a.reduce(:+)

If I enter 1 2 3 4 5 6 7 then it will output 28

Like reduce you can use

a = gets.split(" ").map! {|n| n.to_i}
puts a.inject(:+)

Hope it will help someone.

Upvotes: 1

Aetherus
Aetherus

Reputation: 8888

each won't change the array. You should use map!

a = gets.split(" ").map! {|n| n.to_i}
puts "#{a[0] + a[1]}"

Upvotes: 2

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