Reputation: 1285
I have an array
var a = [
{id: 1, item: 3},
{id: 1, item: 4},
{id: 1, item: 5},
{id: 2, item: 6},
{id: 2, item: 7},
{id: 3, item: 8}
]
I need output like this:
[{id: 1, items: [3, 4, 5]}, {id: 2, items: [6,7]}, {id: 3, items: [8]}]
Upvotes: 0
Views: 34
Reputation: 2632
It's pretty ugly, but then other answers are not pretty either
var a = [
{id: 1, item: 3},
{id: 1, item: 4},
{id: 1, item: 5},
{id: 2, item: 6},
{id: 2, item: 7},
{id: 3, item: 8}
];
var ret = _.chain(a)
.groupBy(elt => elt.id)
.mapValues(elt => _.reduce(elt, (acc, sub) => acc.concat(sub.item),[]))
.map((value, key) => ({id: key, items:value}))
.value();
console.log(ret);
<script src="https://cdn.jsdelivr.net/lodash/4.17.4/lodash.min.js"></script>
Upvotes: 0
Reputation: 27976
Here's a solution that first groups by id
and then maps across the groupings to get the required collection:
let result = _(a)
.groupBy('id')
.map( (group ,id) => ({id: id, items: _.map(group, 'item')}))
.value()
Upvotes: 1