Reputation: 15
I have a problem with the implementation of the breadth-first search algorithm, I have a method that gives me an array of integers from 0-8, in random order. I also have an integer m that tells me which number is blank. Here are the rules:
I get a block of numbers, like:
456
782
301
And lets say that 8 is the blank value, I can swap it with 5, 7, 2, and 0. since they are directly next to it. I have to use breadth-first search to solve this puzzle. Here is the code I have written so far:
package application;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.LinkedHashSet;
import java.util.LinkedList;
import java.util.List;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Vector;
public class Solution {
/******************************************
* Implementation Here
***************************************/
/*
* Implementation here: you need to implement the Breadth First Search
* Method
*/
/* Please refer the instruction document for this function in details */
public static LinkedHashSet<int[]> OPEN = new LinkedHashSet<int[]>();
public static HashSet<int[]> CLOSED = new HashSet<int[]>();
public static boolean STATE = false;
public static int empty;
public static void breadthFirstSearch(int[] num, int m, Vector solution1) {
int statesVisited = 0;
for(int i : num) {
if(num[i] == m) {
empty = i;
}
}
int[] start = num;
int[] goal = {0,1,2,3,4,5,6,7,8};
int[] X;
int[] temp = {};
OPEN.add(start);
while (OPEN.isEmpty() == false && STATE == false) {
X = OPEN.iterator().next();
OPEN.remove(X);
int pos = empty; // get position of ZERO or EMPTY SPACE
if (compareArray(X,goal)) {
System.out.println("SUCCESS");
STATE = true;
} else {
// generate child nodes
CLOSED.add(X);
temp = up(X, pos);
if (temp != null)
OPEN.add(temp);
temp = left(X, pos);
if (temp != null)
OPEN.add(temp);
temp = down(X, pos);
if (temp != null)
OPEN.add(temp);
temp = right(X, pos);
if (temp != null)
OPEN.add(temp);
if(OPEN.isEmpty())
System.out.println("Ending loop");
}
}
}
public static boolean compareArray(int[] a, int[] b) {
for(int i: a)
if(a[i] != b[i])
return false;
return true;
}
public static int[] up(int[] s, int p) {
int[] str = s;
if (p > 3) {
int temp = str[p-3];
str[p-3] = str[p];
str[p] = temp;
}
// Eliminates child of X if its on OPEN or CLOSED
if (!OPEN.contains(str) && CLOSED.contains(str) == false)
return str;
else
return null;
}
public static int[] down(int[] s, int p) {
int[] str = s;
if (p < 6) {
int temp = str[p+3];
str[p+3] = str[p];
str[p] = temp;
}
// Eliminates child of X if its on OPEN or CLOSED
if (!OPEN.contains(str) && CLOSED.contains(str) == false)
return str;
else
return null;
}
public static int[] left(int[] s, int p) {
int[] str = s;
if (p != 0 && p != 3 && p != 6) {
int temp = str[p-1];
str[p-1] = str[p];
str[p] = temp;
}
// Eliminates child of X if its on OPEN or CLOSED
if (!OPEN.contains(str) && CLOSED.contains(str) == false)
return str;
else
return null;
}
public static int[] right(int[] s, int p) {
int[] str = s;
if (p != 2 && p != 5 && p != 8) {
int temp = str[p+1];
str[p+1] = str[p];
str[p] = temp;
}
// Eliminates child of X if its on OPEN or CLOSED
if (!OPEN.contains(str) && CLOSED.contains(str) == false)
return str;
else
return null;
}
public static void print(String s) {
System.out.println(s.substring(0, 3));
System.out.println(s.substring(3, 6));
System.out.println(s.substring(6, 9));
System.out.println();
}
}
This code just immediately ends, and never finds an answer. Perhaps I have done something wrong? Please help.
Please Note: This is my first question on StackOverFlow, so if anyone has any criticisms please tell me and I will fix them right away.
Upvotes: 2
Views: 294
Reputation: 5021
First of all, you have a parameter which isn't doing anything, Vector solution
in:
public static void breadthFirstSearch(int[] num, int m, Vector solution1)
Also you are passing in the position of the zero element which you are representing as m, then assigning a local variable to that position, seems a little pointless to me there's no need to pass in the zero position if you're going to search for it anyway.
Updated breadth first search method:
public static void breadthFirstSearch(int[] num) {
for (int i : num) {
if (num[i] == 0) {
empty = i;
}
}
int[] start = num;
int[] goal = {1, 2, 3, 4, 5, 6, 7, 8, 0};
int[] X;
int[] temp = {};
OPEN.add(start);
while (OPEN.isEmpty() == false && STATE == false) {
X = OPEN.iterator().next();
OPEN.remove(X);
int pos = empty; // get position of ZERO or EMPTY SPACE
if (Arrays.equals(X, goal)) {
System.out.println("SUCCESS");
STATE = true;
} else {
// generate child nodes
CLOSED.add(X);
temp = up(X, pos);
if (temp != null) {
OPEN.add(temp);
}
temp = left(X, pos);
if (temp != null) {
OPEN.add(temp);
}
temp = down(X, pos);
if (temp != null) {
OPEN.add(temp);
}
temp = right(X, pos);
if (temp != null) {
OPEN.add(temp);
}
if (OPEN.isEmpty()) {
System.out.println("Ending loop");
}
}
}
}
The main issue with your program was that within your movement methods up()
, down()
, left()
, right()
. You weren't creating complete copies of the arrays, thus resulting in modifications happening to the original array.
Thus this assignment:
int[] str = s;
must be changed to:
int[] str = new int[s.length];
System.arraycopy(s, 0, str, 0, s.length);
Here's an example of a completed method:
public static int[] up(int[] s, int p) {
int[] str = new int[s.length];
System.arraycopy(s, 0, str, 0, s.length);
if (p > 3) {
int temp = str[p - 3];
str[p - 3] = str[p];
str[p] = temp;
}
// Eliminates child of X if its on OPEN or CLOSED
if (!OPEN.contains(str) && !CLOSED.contains(str)) {
return str;
} else {
return null;
}
}
SIDE NOTE (Not essential):
There are certain permutations of the array which won't result in the goal state. This puzzle itself can have a total number of 9!
configurations, but actually only 9!/2
of these are solvable.
I wrote an algorithm for checking the parity of the puzzle, which can be done as a kind of preprocessing, I used it in order to create random instances for testing the data.
public boolean isSolvable(int[] puzzle) {
boolean parity = true;
int gridWidth = (int) Math.sqrt(puzzle.length);
boolean blankRowEven = true; // the row with the blank tile
for (int i = 0; i < puzzle.length; i++) {
if (puzzle[i] == 0) { // the blank tile
blankRowEven = (i / gridWidth) % 2==0;
continue;
}
for (int j = i + 1; j < puzzle.length; j++) {
if (puzzle[i] > puzzle[j] && puzzle[j] != 0) {
parity = !parity;
}
}
}
// even grid with blank on even row; counting from top
if (gridWidth % 2 == 0 && blankRowEven) {
return !parity;
}
return parity;
}
For the vector
You want to be able to print out the path that has been taken to get to the goal state, I would recommend having a class for the State
such:
private State previousState;
private int[] current;
public State(int[] current, State previousState) {
this.current = current;
this.previousState = previousState
}
public State getPreviouState(){
return previousState;
}
public int[] getCurrentState(){
return currentState;
}
Then when you have the goal State
you can loop through all the previous States to see the path it took.
State current = GOAL;
while(current != null){
System.out.println(Arrays.toString(current));
current = current.getPreviousState();
}
Upvotes: 2
Reputation: 151
The method up(...) has an error:
You have:
str[p] = str[p-3];
Which I'm guessing should be:
str[p] = temp;
Upvotes: 1