lalala
lalala

Reputation: 1201

Only numbers. Input number in React

I'm trying to exclude minus and plus from input, but it's going wrong:

handleChange(event) {
  const value = event.target.value.replace(/\+|-/ig, '');
  this.setState({financialGoal: value});
}

Render input code:

<input style={{width: '150px'}} type="number" value={this.state.financialGoal} onChange={this.handleChange}/>

Upvotes: 102

Views: 404303

Answers (25)

Wagner Tanaka
Wagner Tanaka

Reputation: 1

Instead of using type="number", you can use type="text" like this:

<input
  type="text"
  value={this.state.financialGoal}
  onChange={(event) => {
    const inputValue = event.target.value;
    const sanitizedValue = inputValue.replace(/[^0-9]/g, '');
    this.setState({ financialGoal: sanitizedValue });
  }}
/>

This avoids issues with type="number", such as allowing invalid characters like e, -, or ..

Upvotes: 0

Vinny
Vinny

Reputation: 779

You can do as follow to allow only numbers, backspace, tab, enter, delete, and arrow keys

<input 
    type="text"
    id="phone_number"
    name="phone_number"
    className="grow"
    onKeyDown={(e) => {
        if (!/[0-9]|Backspace|Tab|Enter|Delete|ArrowLeft|ArrowRight/.test(e.key)) {
            e.preventDefault();
        }
    }}
/>

Upvotes: 2

fisch
fisch

Reputation: 128

    <input
                                    
                                    onKeyDown={(event) => {
                            
                                        const filter = ["Backspace", "ArrowRight", "ArrowLeft", "Tab"];
                                        if (!/[0-9]/.test(event.key) && filter.indexOf(event.key) === -1) {
                                            event.preventDefault();
                                        }
                                    }}
                                    
                                />

Upvotes: 0

Sylhare
Sylhare

Reputation: 7059

If you want to handle both ., , and (nothing) for the input as a number then you can use this mix:

<input 
  type='number'
  pattern='[0-9]+([\,|\.][0-9]+)?'
  step='1'
  value={this.state.financialGoal} 
  onChange={this.handleChange}
/>

The e.target.value will be a string that can then be parsed to float when needed (like when passed for back-end call). It means that the financialGoal is still a number but should be in a string format.

Decimal value or no number is usually not handled well by default, so this way I have a controlled string input as a number.

class FinancialApp extends React.Component {
  constructor(props) {
    super(props)
    this.state = {
      financialGoal: '5,5'
    }
    this.handle
  }

  handleChange = (e) => {
    this.setState({
      financialGoal: e.target.value
    })
    console.log(`${e.target.validity.valid} ${this.state.financialGoal}`)
  }

  render() {
    return ( <
      div >
      <
      p > {
        this.state.financialGoal
      } < /p> <
      input placeholder = 'finanical goal'
      type = 'number'
      pattern = '[0-9]+([\,|\.][0-9]+)?'
      step = '1'
      value = {
        this.state.financialGoal
      }
      onChange = {
        this.handleChange
      }
      /> <
      /div>
    )
  }
}

ReactDOM.render( < FinancialApp / > , document.querySelector("#app"))
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="app"></div>

Upvotes: 1

Use a pattern validation in order to allow one point (for decimals) and not allow spaces. You need to pass an arrow function in setState() in order to immediately update the state value, once it will be placed back in the input field.

*considering a class component

Given some context to the state variable.

constructor(props) {
  super(props);
  this.state = {inputValue: ''};
};

The input field content is evaluated against the pattern regex. If both match, the event's validity.valid property is assigned as true, otherwise false:

<input 
 pattern = '[0-9]*\.?[0-9]*' 
 type = 'text'
 value = {this.state.inputValue}
 onChange = {this.handleChange} 
...>

In handleChange, the state is immediately updated if validity.valid is true, otherwise it keeps the previous value (and the text in the input field doesn't change).

handleChange = (e) => {
  this.setState((prevState) => (
    e.target.validity.valid ? {inputValue: e.target.value} : prevState)
  )    
};

Upvotes: 2

Sandeep Rana
Sandeep Rana

Reputation: 309

handleChange(event) {
  const value = event.target.value
  let finalValue;
  Number.isNaN(parseInt(value)) ? finalValue = 0 : finalValue = parseInt(value)

this.setState({financialGoal: finalValue});

}

Upvotes: 0

omalave
omalave

Reputation: 876

The fastest way I found was adding a onKeyPress like this:

<input 
  type="text" 
  name="example"
  value="Type here"
  onKeyPress={(event) => {
      if (!/[0-9]/.test(event.key)) {
          event.preventDefault();
      }
  }}
>

Upvotes: 5

Shinoy Babu
Shinoy Babu

Reputation: 1769

We can use the Terinary operator and do like this. Also using useState to set the values to the object

<input id="cost" name="cost" type="text" onChange = {e=>isNaN(e.target.value)?e.target.value="":setItem({...item,cost:parseInt(e.target.value)})} />     

                   

Upvotes: 1

Shahbaz Shaikh
Shahbaz Shaikh

Reputation: 204

I am using isNaN function of JS to verify whether it is number or not.

const handleChange2 = (e) => {
    if (isNaN(e.target.value)) {
      return;
    }
    const onlyNums = e.target.value.replace(/[^0-9]/g, "");
    setFormData({
      ...formData,
      [e.target.name]: onlyNums,
    });
  };

  const [formData, setFormData] = useState({
    name: "",
    phone: "",
    email: "",
    address: "",
  });

  <input
    value={phone}
    onChange={(e) => handleChange2(e)}
    placeholder="Phone"
    type="text"
    name="phone"
    required
   />

Note:The value stored in the state will string, if you want it to be a number/int just use Number to convert it into integer. ex: let phone= Number(formData.phone)

Upvotes: 4

Akinjiola Toni
Akinjiola Toni

Reputation: 678

You can try this solution, since onkeypress will be attached directly to the DOM element and will prevent users from entering invalid data to begin with.

So no side-effects on react side.

<input type="text" onKeyPress={onNumberOnlyChange}/>

const onNumberOnlyChange = (event: any) => {
    const keyCode = event.keyCode || event.which;
    const keyValue = String.fromCharCode(keyCode);
    const isValid = new RegExp("[0-9]").test(keyValue);
    if (!isValid) {
       event.preventDefault();
       return;
    }
};

Upvotes: 0

Phat Tran
Phat Tran

Reputation: 3860

Simply way in React

<input
      onKeyPress={(event) => {
        if (!/[0-9]/.test(event.key)) {
          event.preventDefault();
        }
      }}
    />

Upvotes: 117

Gergely M
Gergely M

Reputation: 733

Here's my solution of plain Javascript

Attach a keyup event to the input field of your choice - id in this example.
In the event-handler function just test the key of event.key with the given regex.

In this case if it doesn't match we prevent the default action of the element - so a "wrong" key-press within the input box won't be registered thus it will never appear in the input box.

  let idField = document.getElementById('id');

  idField.addEventListener('keypress', function(event) {
    if (! /([0-9])/g.test(event.key)) {
      event.preventDefault();
    }
  });

The benefit of this solution may be its flexible nature and by changing and/or logically chaining regular expression(s) can fit many requirements. E.g. the regex /([a-z0-9-_])/g should match only lowercase English alphanumeric characters with no spaces and only - and _ allowed.

Note: that if you use /[a-z]/gi (note the i at the end) will ignore letter case and will still accept capital letters.

Upvotes: 3

pa1nd
pa1nd

Reputation: 432

Here is a solution with onBlur, it can be very helpful as it also allows you to format the number the way you need it without requiring any black magic or external library.

2020 React Hooks

const toNumber = (value: string | number) => {
    if (typeof value === 'number') return value
    return parseInt(value.replace(/[^\d]+/g, ''))
}

const formatPrice = (price: string | number) => {
  return new Intl.NumberFormat('es-PY').format(toNumber(price))
}
<input
    defaultValue={formatPrice(price)}
    onBlur={e => {
      const numberValue = toNumber(e.target.value)
      setPrice(numberValue)
      e.target.value = formatPrice(numberValue)
    }}
    type='tel'
    required
/>

How it works:

  • Set initial value via defaultValue
  • Allow user to freely type anything they feel
  • onBlur (once the input looses focus):
    • replace any character that is not a digit with an empty string
    • setState() or dispatch() to manage state
    • set the value of the input field to the numeric value and apply optional formatting

Pay attention: In case your value come from a async source (e.g. fetch): Since defaultValue will only set the value on the first render, you need to make sure to render the component only once the data is there.

Upvotes: 3

SouMitya chauhan
SouMitya chauhan

Reputation: 331

 <input
        className="input-Flied2"
        type="TEXT"
        name="userMobileNo"
        placeholder="Moble No"
        value={phonNumber}
        maxLength="10"
        onChange={handleChangeInput}
        required
      />

  const handleChangeInput = (e) => {
const re = /^[0-9\b]+$/; //rules
if (e.target.value === "" || re.test(e.target.value)) {
  setPhoneNumber(e.target.value);
}

};

Upvotes: 2

After reading all the answers but none really working for numbers only with copy and paste I came up with this solution.

  • parseInt solution: fails as parseInt("2a") is valid;
  • onKeyup sulution: fails on copy and paste, backspace;
  • key.which solution: will probably fail on copy and paste;
  • type="number" solution: fails on long numbers as javascript converts 40817810000000023511 into 40817810000000023500 because it is 53 bit language
<input
    name="address.line1"
    value={values.address.line1}
    onChange={(event: any) => {
      if (isFinite(event.target.value)) {
      // UPDATE YOUR STATE (i am using formik)
      setFieldValue("address.line1", event.target.value);
    }
  }}
/>

Upvotes: 0

Samuli Hakoniemi
Samuli Hakoniemi

Reputation: 19049

I tried to mimic your code and noticed that there's an issue on React with <input type='number' />. For workaround, check this example and try it yourself: https://codepen.io/zvona/pen/WjpKJX?editors=0010

You need to define it as normal input (type='text') with pattern for numbers only:

    <input type="text" pattern="[0-9]*"
     onInput={this.handleChange.bind(this)} value={this.state.financialGoal} />

And then to compare the validity of input:

const financialGoal = (evt.target.validity.valid) ? 
  evt.target.value : this.state.financialGoal;

The biggest caveat on this approach is when it comes to mobile --> where keyboard isn't in numeric but in normal alphabetic format.

Upvotes: 80

Foram Shah
Foram Shah

Reputation: 115

Set class on your input field:

$(".digitsOnly").on('keypress',function (event) {
    var keynum
    if(window.event) {// IE8 and earlier
       keynum = event.keyCode;
    } else if(event.which) { // IE9/Firefox/Chrome/Opera/Safari
       keynum = event.which;
    } else {
       keynum = 0;
    }

    if(keynum === 8 || keynum === 0 || keynum === 9) {
        return;
    }
    if(keynum < 46 || keynum > 57 || keynum === 47) {
        event.preventDefault();
    } // prevent all special characters except decimal point
}

Restrict paste and drag-drop on your input field:

$(".digitsOnly").on('paste drop',function (event) {
    let temp=''
    if(event.type==='drop') {
        temp =$("#financialGoal").val()+event.originalEvent.dataTransfer.getData('text');
        var regex = new RegExp(/(^100(\.0{1,2})?$)|(^([1-9]([0-9])?|0)(\.[0-9]{1,2})?$)/g); //Allows only digits to be drag and dropped
        if (!regex.test(temp)) {
           event.preventDefault();
           return false;
        }
    } else if(event.type==='paste') {
        temp=$("#financialGoal").val()+event.originalEvent.clipboardData.getData('Text')
        var regex = new RegExp(/(^100(\.0{1,2})?$)|(^([1-9]([0-9])?|0)(\.[0-9]{1,2})?$)/g); //Allows only digits to be pasted
        if (!regex.test(temp)) {
           event.preventDefault();
           return false;
        }
    }
}

Call these events in componentDidMount() to apply the class as soon as the page loads.

Upvotes: -4

Skid Kadda
Skid Kadda

Reputation: 482

2019 Answer Late, but hope it helps somebody

This will make sure you won't get null on an empty textfield

  • Textfield value is always 0
  • When backspacing, you will end with 0
  • When value is 0 and you start typing, 0 will be replaced with the actual number
// This will make sure that value never is null when textfield is empty

const minimum = 0;   

export default (props) => {
    const [count, changeCount] = useState(minimum);

    function validate(count) {
        return parseInt(count) | minimum
    }

    function handleChangeCount(count) {
        changeCount(validate(count))
    }

    return (
        <Form>
            <FormGroup>
                <TextInput
                    type="text"
                    value={validate(count)}
                    onChange={handleChangeCount}
                />
            </FormGroup>
            <ActionGroup>
                <Button type="submit">submit form</Button>
            </ActionGroup>
        </Form>
    );
};

Upvotes: 1

Alexander Kireyev
Alexander Kireyev

Reputation: 10825

The most effective and simple solution I found:

<input
    type="number"
    name="phone"
    placeholder="Phone number"
    onKeyDown={e => /[\+\-\.\,]$/.test(e.key) && e.preventDefault()}
/>

Upvotes: 3

Marquistador
Marquistador

Reputation: 1951

Define an input with an onChange() method like below (in my case, childState contains the state, passed down to this child component).

<input
   ...
   value={this.props.childState.volume}
   ...
   onChange={(e) => handleChangeInteger(e, {volume: e.target.value})}
/>

One approach I used was to install validatorJS (npm install validator --save)

I then defined a function handleChangeInteger, which takes an object that will be used to change your state, in this case, {volume: e.target.value}. Note: I needed the OR condition to allow my input to be blank, otherwise it would not let the user backspace (delete) the last integer if they wanted the field blank.

const handleChangeInteger = (e, obj_to_return) => {
  if (validator.isInt(e.target.value) || e.target.value == '') {
    this.props.childSetState(obj_to_return)
  }
}

The user will now not be allowed to type anything other than backspace, 0-9, or e (this is a number..) in the input field.

I referenced this post to create my solution: https://stackoverflow.com/a/45676912/6169225

Upvotes: 0

Zhijian
Zhijian

Reputation: 109

Solution

Today I find use parseInt() is also a good and clean practice. A onChange(e) example is below.

Code

onChange(e){
    this.setState({[e.target.id]: parseInt(e.target.value) ? parseInt(e.target.value) : ''})
}

Explanation

  1. parseInt() would return NaN if the parameter is not a number.
  2. parseInt('12a') would return 12.

Upvotes: 9

Jimmay
Jimmay

Reputation: 722

If you want to maintain input type='number' (probably for mobile devices to trigger the numeric keyboard) you should use onInput instead of onChange to capture your event changes.

Using onInput fixed a bug where typing text into a number input would bypass the validation I had assigned to it in onChange. Once I fixed this function to be called in onInput it triggered in all instances.

Here's an example of what I'm doing:

<input
    type='number'
    id={`player${index}Score`}
    className='form-control'
    pattern='[0-9]{0,5}'
    onInput={(event) => this.enterScore(event, index)}
    value={this.props.scoreLabel(this.state.scores[index])}
/>

I hope this helps!

EDIT - 08-03-2018:

I came up with a better solution. Use type='tel' along with a pattern regex within the input component itself.

The nuts and bolts of how I wired this up is here:

class Input extends React.Component {
  state = {message: '3'};

  updateNumber = (e) => {
    const val = e.target.value;
    // If the current value passes the validity test then apply that to state
    if (e.target.validity.valid) this.setState({message: e.target.value});
    // If the current val is just the negation sign, or it's been provided an empty string,
    // then apply that value to state - we still have to validate this input before processing
    // it to some other component or data structure, but it frees up our input the way a user
    // would expect to interact with this component
    else if (val === '' || val === '-') this.setState({message: val});
  }

  render() {
    return (
      <input
        type='tel'
        value={this.state.message}
        onChange={this.updateNumber}
        pattern="^-?[0-9]\d*\.?\d*$"
      />
    );
  }
}

ReactDOM.render(<Input />, document.getElementById('main'));

I have an example of this working on Codepen here

Upvotes: 27

Stanislav Stadnyk
Stanislav Stadnyk

Reputation: 29

Maybe, it will be helpful for someone
Recently I used this solution for my App
I am not sure that is a correct solution but it works fine.

this.state = {
    inputValue: "",
    isInputNotValid: false
}

handleInputValue = (evt) => {
    this.validationField(evt, "isInputNotValid", "inputValue");
}

validationField = (evt, isFieldNotValid, fieldValue ) => {
   if (evt.target.value && !isNaN(evt.target.value)) {
        this.setState({ 
            [isFieldNotValid]: false,
            [fieldValue]: evt.target.value,
        });
    } else {
        this.setState({ 
            [isFieldNotValid]: true,
            [fieldValue]: "",
        });
    }
}

<input className={this.state.isInputNotValid ? "error" : null} type="text" onChange="this.handleInputValue" />

The main idea, that state won't update till the condition isn't true and value will be empty.
Don't need to use onKeyPress, Down etc.,
also if you use these methods they aren't working on touch devices

Upvotes: -1

francojohnc
francojohnc

Reputation: 815

one line of code

<input value={this.state.financialGoal} onChange={event => this.setState({financialGoal: event.target.value.replace(/\D/,'')})}/>

Upvotes: 63

Abdennour TOUMI
Abdennour TOUMI

Reputation: 93163

  • To stop typing, use onKeyPress not onChange .

  • Using event.preventDefault() inside onKeyPress means STOP the pressing event .

  • Since keyPress handler is triggered before onChange, you have to check the pressed key (event.keyCode), NOT the current value of input (event.target.value)

    onKeyPress(event) {
      const keyCode = event.keyCode || event.which;
      const keyValue = String.fromCharCode(keyCode);
      if (/\+|-/.test(keyValue))
        event.preventDefault();
    }
    

Demo below 👇🏻

const {Component} = React; 

class Input extends Component {
  

  onKeyPress(event) {
   const keyCode = event.keyCode || event.which;
   const keyValue = String.fromCharCode(keyCode);
    if (/\+|-/.test(keyValue))
      event.preventDefault();
  }
  render() {
  
   return (
   <input style={{width: '150px'}} type="number" onKeyPress={this.onKeyPress.bind(this)} />

   )
  }
 
}

ReactDOM.render(<Input /> , document.querySelector('#app'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

<section id="app"></section>

Upvotes: 24

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