CODEWITHSUNDEEP
javascript
user7662982
user7662982

Reputation:

strict mode does not appear the use of the implicit arguments?

Is this correct? Is this new?

I mean the implicit arguments that each function has btw.

I noticed that my code is failing when I use arguments in strict mode, if I remove strict mode not problem ... is this new or has it always been this way ?

console.log('foo.js running');
(function() {
  // 'use strict';
  // unexpected arguments in strict mode ...

and here is where I use it:

  _.extend = function(obj) {
    _.each(Array.prototype.slice.call(arguments, 1), function (object) {
      _.each(object, function(val, key){
        obj[key] = val;
      })
    });
    return obj;
  }

Upvotes: 0

Views: 61

Answers (1)

T.J. Crowder
T.J. Crowder

Reputation: 1074475

No, strict mode does not prevent use of arguments. It does change it slightly: The arguments object is no longer tied to the named parameters, so:

function loose(a) {
  console.log(a);
  arguments[0] = "bar"; // Changes `a`
  console.log(a);
}
function strict(a) {
  "use strict";
  console.log(a);
  arguments[0] = "bar"; // Does not change `a`
  console.log(a);
}
loose("foo");
strict("foo");

Upvotes: 1

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