Reputation: 21
My question is pretty specific, I think. My program is supposed to store 10 names, and their corresponding phone numbers into an array. I want to sort the names/numbers by phone numbers, ascending order, and then output the array in the sorted order. Thanks for the help! Any and all help is appreciated. What I have so far:
using namespace std;
main()
{
string name[10][2];
int x;
cout << "Please input 10 names";
for(int i = 0; i < 10; i++){
cin >> name[i][x];
}
int i = 0;
cout << "Please input their corresponding numbers";
for(x = 0; x < 10; x++){
cin >> name[i][x];
}
}
EDIT: Would it be possible(not as hassling) to instead do this but with a parallel array storing a string(name) and an int(number) and sort it by the int?(Of course, while keeping the names by their corresponding number) If so, how could I change it from a two-dimensional to a parallel array?(Or just pointing me in the right direction would be greatly appreciated) :)
Upvotes: 0
Views: 87
Reputation: 10939
You will want to use a vector of pairs. This is in this case more convenient than a map because you want to sort by value rather than by key. There are also methods to sort a map by value (see question Sorting std::map using value), but for this purpose a vector of pairs seems appropriate.
If you want to have a constant memory array instead of a dynamic memory array (std::vector
) then use std::array<std::pair<std::string,int>, N>
, where N
is the number of elements.
Needs C++14 because of the template lambda.
#include <algorithm>
#include <iostream>
#include <utility>
#include <vector>
int main()
{
std::vector<std::pair<std::string,int>> phonebook;
phonebook.reserve(10);
std::cout << "Please input a name and a number\n";
for (int i = 0; i < 10; ++i) {
std::cout << "Name: ";
std::string name;
std::cin >> name;
std::cout << "Number: ";
int number;
std::cin >> number;
phonebook.push_back({name, number});
}
std::sort( std::begin(phonebook),
std::end(phonebook),
[] (auto a, auto b) { return a.second < b.second; });
for (auto const& entry : phonebook)
{
std::cout << entry.first << ' ' << entry.second << '\n';
}
}
Upvotes: 1