Reputation: 384
I have this table
| BookID | BookTitle | NumberOfPages | NoOfCopies |
+--------+--------------------------------+---------------+------------+
| 1 | The Help | 444 | 4 |
| 2 | The Catcher in the Rye | 277 | 10 |
| 3 | Crime and Punishment | 545 | 2 |
| 4 | The Brothers Karamazov | 795 | 1 |
| 5 | A Crown of Wishes | 369 | 12 |
| 6 | The Fireman | 752 | 3 |
| 7 | Fahrenheit 451 | 174 | 9 |
| 8 | The Hobbit | 366 | 1 |
| 9 | Lord of Emperors | 560 | 4 |
| 10 | Holy Bible: King James Version | 1590 | 11 |
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When I insert a book title and expect it to return the book id, it always returns an empty set
so far, I have tried these queries.->book_info is the name of the table:
select BookID from book_info where ucase(BookTitle) = ' THE HELP% ';
select BookID from book_info where BookTitle = ' The Help ';
select BookID from book_info where lcase(trim(BookTitle) = 'the help';
but none of them worked.
Note I don't rely on sql in my job.
Upvotes: 4
Views: 2114
Reputation: 2677
The issue here is with the operator you are using and the value you are function you are expecting from it, =
operator checks for the exact match that's why your queries are returning no records:
select BookID from book_info where ucase(BookTitle) = ' THE HELP% ';
select BookID from book_info where BookTitle = ' The Help ';
select BookID from book_info where lcase(trim(BookTitle) = 'the help';
And one more thing that is:
MySQL queries are not case-sensitive by default.
So you don't need to add the string methods here to change the values case.
We usually use the %
with LIKE
only like this:
select BookID from book_info where ucase(BookTitle) LIKE '%THE HELP%';
In this query LIKE %THE HELP%
will match all the string having THE HELP
in them;
Upvotes: 2
Reputation: 2599
you need to use like if you want to use "%"
when you use "=" you need to sure it is same. even space also count
select BookID from book_info where BookTitle LIKE 'THE HELP%';
Upvotes: 2