Reputation: 412
I have the following problem:
Let's say I have an array defined like this:
A = np.array([[1,2,3],[4,5,6],[7,8,9]])
What I would like to do is to make use of Numpy multiple indexing and set several elements to 0. To do that I'm creating a vector:
indices_to_remove = [1, 2, 0]
What I want it to mean is the following:
The result should be the array [[1,0,3],[4,5,0],[0,8,9]]
I've managed to get values of the elements I would like to modify by following code:
values = np.diagonal(np.take(A, indices, axis=1))
However, that doesn't allow me to modify them. How could this be solved?
Upvotes: 3
Views: 1750
Reputation: 221534
You could use integer array indexing
to assign those zeros -
A[np.arange(len(indices_to_remove)), indices_to_remove] = 0
Sample run -
In [445]: A
Out[445]:
array([[1, 2, 3],
[4, 5, 6],
[7, 8, 9]])
In [446]: indices_to_remove
Out[446]: [1, 2, 0]
In [447]: A[np.arange(len(indices_to_remove)), indices_to_remove] = 0
In [448]: A
Out[448]:
array([[1, 0, 3],
[4, 5, 0],
[0, 8, 9]])
Upvotes: 2