CODEWITHSUNDEEP
javascript
intangibles
intangibles

Reputation: 153

For loop return an index number matching

I'm having trouble with a for loop. I want to return the index that matches with num against fruits. When num=2, I want it to return "apple". What am I doing wrong?

    var num=2;
    var fruits = ["Banana", "Orange", "Apple", "Mango"];
    for (var i=0;i <fruits.length;i++) {
      if (fruits[i] === num) {
        console.log("matched, it is" + fruits[num])
      } else {
        console.log("did not match")
      }
    }

Upvotes: 2

Views: 95

Answers (3)

Kirti Thorat
Kirti Thorat

Reputation: 53038

The condition that you should be checking against is

if(i === num) instead of if(fruits[i] === num).

You want to compare index i against number num and not the value at index i in fruits array against num.

For example: fruits[0] is "Banana", fruits[1] is "Orange",...so on. What you are doing is comparing "Banana", "Orange",...etc against num value 2 when you should be comparing value of i which goes from 0,1,..3 against num value 2.

Also, like @Kamyar pointed out, you can directly access fruits[num], probably after a sanity check in case fruits gets populated from an outside source:

var num=2;
var fruits = ["Banana", "Orange", "Apple", "Mango"];
if(fruits != null && num >= 0 && num < fruits.length) {
    console.log("matched, it is " + fruits[num])
}
else{
    console.log("did not match")
}

Upvotes: 2

Alex
Alex

Reputation: 11579

You have to compare num with array index i:

if (i == num) {
   console.log("matched, it is" + fruits[num])
}

Upvotes: 1

kind user
kind user

Reputation: 41893

if (fruits[i] === num) {...} - fruits[i] is an element inside the fruits array at i position, not an index. Compare it with the index i === num instead.

var num = 2,
    fruits = ["Banana", "Orange", "Apple", "Mango"];
    
for (var i = 0; i < fruits.length; i++) {
  if (i === num) {
    console.log("matched, it is " + fruits[num])
  } else {
    console.log("did not match")
  }
}

Upvotes: 1

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