CODEWITHSUNDEEP
pythonipython
css_wp
css_wp

Reputation: 203

Volume of sphere in python

I can easily calculate the volume of a sphere in python using this code. 

import math

radius = input("Enter Radius: ")
print("Radius: " + str(radius))

r = float(radius)

volume = 4.0/3.0 * math.pi * (r*r*r)
print("Volume: " + str(round(volume,2)))

Now my plan is to find the volume in n dimension. The equation I have derived to find the volume and graphical changes of volume is that enter image description here

I wanted to use like this 

import math

dimension = input("Enter dimension: ")
print("dimension: " + str(dimension))
n = float(dimension)
volume = math.pi^(n/2)/math.gamma(n/2 + 1)
print("Volume: " + str(round(volume,2)))

It's not working. Can you help me finding the volume for different dimension with getting the plot for the volume of the sphere?

Upvotes: 0

Views: 11561

Answers (2)

eyllanesc
eyllanesc

Reputation: 244311

You must change:

volume = math.pi(n/2)^2/math.gamma(n/2 + 1)

to:

volume = math.pi**(n/2)/math.gamma(n/2 + 1)

Complete code:

import math

dimension = input("Enter dimension: ")
print("dimension: " + str(dimension))
n = float(dimension)
volume = math.pi**(n/2)/math.gamma(n/2 + 1)
print("Volume: " + str(round(volume,4)))

Input:

Enter dimension: 3

Output:

dimension: 3
Volume: 4.1888

Additional:

import math

import matplotlib.pyplot as plt
x = []
y = []
for dimension in range(100):
    n = float(dimension)
    volume = math.pi**(n/2)/math.gamma(n/2 + 1)
    x.append(n)
    y.append(volume)

plt.plot(x, y)
plt.show()

enter image description here

Upvotes: 3

JacobIRR
JacobIRR

Reputation: 8966

Looks like pow() is what you need:

import math

dimension = input("Enter dimension: ")
print("dimension: " + str(dimension))
n = float(dimension)
volume = pow(math.pi,(n/2))/math.gamma(n/2 + 1)
print("Volume: " + str(round(volume,2)))

pow(x,y) Returns x to the power y.

Upvotes: 0

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