CODEWITHSUNDEEP
pythonloopsdictionary
LucSpan
LucSpan

Reputation: 1971

Replace part of string of elements of lists in dictionary

Set-up

I have a dictionary where each key contains a list of at least one string element.

Here is a part of the dictionary,

d = {
  'Bergen-Enkheim': ['Bergen-Enkheim'],
  'Bornheim/Ostend': ['Ostend,\xa0Bornheim'],
  'Harheim': ['Harheim'],
  'Innenstadt I': ['Altstadt,\xa0Bahnhofsviertel,\xa0Gallus,'
                   '\xa0Gutleutviertel,\xa0Innenstadt']
}

Problem

Most of the elements start with \xa0 which I want to replace with a white space.

I tried the following loop,

for key in d:
   for x in d[key]:
       x = x.replace('\xa0', ' ')

but d stays the same. How do I replace the unwanted characters with a white space?

Upvotes: 0

Views: 841

Answers (3)

Zohaib Ijaz
Zohaib Ijaz

Reputation: 22875

You can iterate over keys and then update values

for key in d:
    d[key] = [s.replace('\xa0', '') for s in d[key]]

Upvotes: 1

Jared Goguen
Jared Goguen

Reputation: 9010

Strings are immutable, so x.replace(...) produces a new string rather than changing the existing string in the dictionary list. Then, the statement x = ... updates x to be a name for the new string. In short, you have to change the entry in the dictionary list explicitly.

for key in d2:
   for i, x in enumerate(d2[key]):
       d2[key][i] = x.replace('\xa0', ' ')

Upvotes: 1

Laurent LAPORTE
Laurent LAPORTE

Reputation: 22942

You can use a classic iteration over the values:

for values in d.values():
    values[:] = [x.replace('\xa0', ' ') for x in values]

Each list is modified in-place.

Upvotes: 1

Related Questions