CODEWITHSUNDEEP
phpmysql
Mimi
Mimi

Reputation: 125

Switch case with two SQL requirements

I have a form select, where I can choose between a weekday and and true/false. I made a switch case statement, where some is working. With my query I can echo out wednesday and if football is 0 correctly. But if the weekday is wednesday and football is 1 I still get the result from 0.

Am I using the switch statement incorrectly?

weekday can be we wednesday or saturday

football can be 0 or 1 (0 = false, 1 = true)

HTML

<select name="weekday" class="form-control selectpicker" >
        <option value=" ">Select Weekday</option>
        <option value="wednesday">Wednesday</option>
        <option value="saturday">Saturday</option>
</select>
<select name="football" class="form-control selectpicker" >
        <option value=" " >Practice</option>
        <option value="1">Yes</option>
        <option value="0">No</option>
</select>

PHP

$sql = "SELECT id, weekday, football FROM footballTable";

      if(isset($_POST['weekday'], $_POST['football'])) {
        switch($_POST['weekday'], $_POST['football']){
          case 'wednesday':
              $sql .= " WHERE weekday LIKE 'Wednesday' AND football = '0' OR football = '1'";
          break;
          
          
          case 'saturday':
              $sql .= " WHERE weekday LIKE 'Saturday'";
          break;

        }
      }
      $sql .= " ORDER BY RAND ( ) LIMIT 3";

Upvotes: 0

Views: 90

Answers (1)

Barmar
Barmar

Reputation: 782130

You need separate switch/case statements for the two variables.

$sql = "SELECT id, weekday, football FROM footballTable WHERE 1=1";
switch ($_POST['weekday'] ?? '') {
    case 'wednesday':
        $sql .= " AND weekday = 'Wednesday'";
        break;
    case 'saturday':
        $sql .= " AND weekday = 'Saturday'";
        break;
}
switch ($_POST['football'] ?? '') {
    case '0':
    case '1':
        $sql .= " AND football = '{$_POST['football']}'";
        break;
}
$sql .= " ORDER BY RAND() LIMIT 3";

Upvotes: 1

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