CODEWITHSUNDEEP
python
user5228393
user5228393

Reputation:

How to remove characters from the odd numbered string?

If I have a string like this: ABCDE

I want to read two characters at a time (AB then CD) and remove the remaining characters (E) which cannot be read in tuples or in two's. How would I remove those characters?

I have this code below so far:

s = 'ABCDE'

for (first, second) in zip(s[0::2], s[1::2]):
    if not first or not second:
        if first:
                s.replace(first, '')
                continue
        else:
                s.replace(second, '')
                continue
    print first, second

print s

This code prints (A B C D) which is good but I want to remove that extra E in the for loop which I am trying to do with the if statement. I check if the either the first or second variable of the tuple is an empty string and then remove whichever one isn't an empty string from the original s variable.

This above code doesn't seem to work. Does anyone have a different suggestion or how I can improve this?

Upvotes: 2

Views: 488

Answers (2)

nevets1219
nevets1219

Reputation: 7706

str = "ABCDE"

for i, k in zip(str[::2], str[1::2]):
    print(i + k)

Outputs:

AB
CD

Upvotes: 0

Right leg
Right leg

Reputation: 16730

If you want to remove the last character in case the string's length is odd:

word = "ABCDE"

if len(word) % 2 == 1:
    word = word[:-1]

Now if you want to read the characters two at a time, here is a more instinctive way:

for i in range(len(word) // 2):
    print(word[2*i:2*i+2])

The latter will even drop the last character for you.

Upvotes: 3

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