CODEWITHSUNDEEP
javascript
user7839191
user7839191

Reputation:

How to sort objects by value

Say you have the following object in JS:

let obj = {a: 24, b: 12, c:21; d:15};

How can 'obj' be transformed into an array of the keys of the object, sorted by the values?

Upvotes: 11

Views: 25306

Answers (5)

nnnnnn
nnnnnn

Reputation: 150010

let obj = {a: 24, b: 12, c:21, d:15};

// Get an array of the keys:
let keys = Object.keys(obj);

// Then sort by using the keys to lookup the values in the original object:
keys.sort((a, b) => obj[a] - obj[b]);

console.log(keys);

Note that the above could be done in one line if desired with Object.keys(obj).sort(...). The simple .sort() comparator function shown will only work for numeric values. Swap a and b to sort in the opposite direction.

Upvotes: 15

Saghachi
Saghachi

Reputation: 945

If the purpose is just monitoring the sorted object in console, I suggest log the object in console with console.table(obj) instead of console.log(obj) and the result will be sortable for both key and value, asc and desc in fastest way with no extra process. enter image description here

Upvotes: -1

Josep Vicent Ibanez
Josep Vicent Ibanez

Reputation: 1748

Wrapped in a function with ASC or DESC.

const myobj = {a: 24, b: 12, c:21, d:15};

function sortObjectbyValue(obj={},asc=true){ 
   const ret = {};
   Object.keys(obj).sort((a,b) => obj[asc?a:b]-obj[asc?b:a]).forEach(s => ret[s] = obj[s]);
   return ret
}

console.log(sortObjectbyValue(myobj))

Upvotes: 1

Ashutosh Ranjan
Ashutosh Ranjan

Reputation: 642

here is the way to get sort the object and get sorted object in return

let sortedObject = {}
sortedObject = Object.keys(yourObject).sort((a, b) => {
                        return yourObject[a] - yourObject[b] 
                    }).reduce((prev, curr, i) => {
                        prev[i] = yourObject[curr]
                        return prev
                    }, {});

you can customise your sorting function as per your requirement

Upvotes: 1

Younis Ar M
Younis Ar M

Reputation: 941

var obj  = {
  a: 24, b: 12, c:21, d:15
};
var sortable = [];
for (var x in obj ) {
    sortable.push([x, obj[x]]);
}

sortable.sort(function(a, b) {
    return a[1] - b[1];
});

console.log(sortable)

Upvotes: 1

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