Reputation: 23
I try to select value of node from soap message (with gt and lt symbols) , but cant do that, i can only get body (root.Body) and other nodes are not visible, it is empty result. What i'm making wrong? Thanks!
import groovy.util.slurpersupport.Node
import groovy.util.slurpersupport.NodeChild
import groovy.xml.XmlUtil
String source=
'''<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<ns0:GetListBy_QualificationResponse xmlns:ns0="urn:WS_CTM_People_ICEVA">
<ns0:getListValues>
<ns0:Person_ID>PPL000000301739</ns0:Person_ID>
<ns0:Submitter>soehler</ns0:Submitter>
<ns0:Profile_Status>Enabled</ns0:Profile_Status>
<ns0:Locale2>en_US</ns0:Locale2>
<ns0:VIP>No</ns0:VIP>
<ns0:Client_Sensitivity>Standard</ns0:Client_Sensitivity>
</ns0:getListValues>
</ns0:GetListBy_QualificationResponse>
</soapenv:Body>
</soapenv:Envelope>'''
def root = new XmlSlurper().parseText(source)
def Submitter =root.Body.GetListBy_QualificationResponse.getListValues.'*'.find { node->
node.name() == 'Submitter'
}
Upvotes: 2
Views: 236
Reputation: 21379
It is because the xml is escaped. In order to be able to retrieve the data property, it is required to unescape the xml string and pass it XmlSlurper
.
Here is how it can be done:
String source='''<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<ns0:GetListBy_QualificationResponse xmlns:ns0="urn:WS_CTM_People_ICEVA">
<ns0:getListValues>
<ns0:Person_ID>PPL000000301739</ns0:Person_ID>
<ns0:Submitter>soehler</ns0:Submitter>
<ns0:Profile_Status>Enabled</ns0:Profile_Status>
<ns0:Locale2>en_US</ns0:Locale2>
<ns0:VIP>No</ns0:VIP>
<ns0:Client_Sensitivity>Standard</ns0:Client_Sensitivity>
</ns0:getListValues>
</ns0:GetListBy_QualificationResponse>
</soapenv:Body>
</soapenv:Envelope>'''
//map the unescape characters
def map = ['<' : '<', '>' : '>', '"' : '"', ''':'\'', '&':'&']
//Replace them in source string
map.collect {k,v -> source = source.replaceAll(k,v)}
//Now parse it
def root = new XmlSlurper().parseText(source)
//Get the submitter
def submitter = root.'**'.find { it.name() == 'Submitter' }
println submitter
You can quickly try online Demo
Upvotes: 1