CODEWITHSUNDEEP
iosregexnsregularexpression
Rathakrishnan Ramasamy
Rathakrishnan Ramasamy

Reputation: 1612

How to write Regex?

I have NSString as like this

/:012/:^_^/:^$^ some string

How can I extract the words which starts with /: using Regex (NSRegularExpression), Kindly assist. Thanks

Upvotes: 1

Views: 102

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626699

You may use

NSString *pattern = @"/:\\S*?(?=/:|\\s|$)";

See the regex demo.

Details:

  • /: - a /: substring
  • \S*? - zero or more chars other than whitespace, as few as possible up to (but excluding) the first occurrence of the following:
  • (?=/:|\s|$) - either /: substring, or whitespace or end of string.

Objective-C demo:

NSError *error = nil;
NSString *pattern = @"/:\\S*?(?=/:|\\s|$)";
NSString *string = @"/:012/:^_^/:^$^ some string";
NSRange range = NSMakeRange(0, string.length);
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&error];
NSArray *matches = [regex matchesInString:string options:0 range:range];
for (NSTextCheckingResult *match in matches) {
   NSRange matchRange = [match range];
   NSString *m = [string substringWithRange:matchRange];
   NSLog(@"Matched string: %@", m);
}

Results:

Matched string: /:012
Matched string: /:^_^
Matched string: /:^$^

Upvotes: 1

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