CODEWITHSUNDEEP
pythonlistcounter
Daan
Daan

Reputation: 41

Python collections Counter not working

I'm trying to use the Counter() function, which is usually simple and works without issue..

I've got the following:

name_freq = []

for names in list.names:

    name_freq.append(names)

print(Counter(name_freq).most_common(3))

and I'm running into a really strange issue. It counts every single item as 1, even duplicates.

Example count result: [{'bob':1, 'bill':1, 'bob':1}]

I didn't even think that was possible in Python list[]. The spelling and capitalization is the exact same.

Any ideas why this is happening?

Upvotes: 3

Views: 3719

Answers (4)

Fuji Komalan
Fuji Komalan

Reputation: 2047

import collections
name_freq = []
names= ['a','b','a','d','e','e','e','a']

for name in names:

    name_freq.append(name)

print(collections.Counter(name_freq).most_common(3))

RESULT

[('a', 3), ('e', 3), ('b', 1)]

Upvotes: 0

EvilSmurf
EvilSmurf

Reputation: 864

Works also for me with a simple tuple. Try if this works. If, focus your effort on the list.names object

from collections import Counter

name_freq = []
list_names = ('bob', 'bill', 'jim', 'john', 'bob')

for names in list_names:

    name_freq.append(names)

print(Counter(name_freq).most_common(3))

Upvotes: 2

Rajani B
Rajani B

Reputation: 203

 nameoverall =[]
 names =[["aa","bb","cc"],["aa","cc"],["dd"],["ee"]]
 for namelist in names:
     nameoverall.extend(namelist)

 print(Counter(nameoverall).most_common(3))

Upvotes: 0

bigbounty
bigbounty

Reputation: 17368

Your code is working perfectly in my system. Run it once again.

Upvotes: 0

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