CODEWITHSUNDEEP
iosswiftmodel-view-controllersegue
jin
jin

Reputation: 57

swift prepare segue not working

CalViewController:

let brain =CalculatorBrain()
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    let graph = GraphController()
    graph.brain.record = brain.record
}

GraphViewController:

var brain = CalculatorBrain() {
    didSet {
        draw.variables = ["M": 1]
        let value = brain.evaluate(using: draw.variables)
        print(value)
//at that time outlet didn't set it prints the value work just fine
    }
}

@IBOutlet weak var graphView: GraphView! {
    didSet {
        draw.variables = ["M": 1]
        let value = brain.evaluate(using: draw.variables)
        print(value)
//when outlet got set it not working it print nothing
 }
}

I just can't figure out why and how to solve this any idea will be appreciate

Upvotes: 0

Views: 787

Answers (1)

Scott Thompson
Scott Thompson

Reputation: 23701

The UIStoryboardSegue contains the actual view controller that you are transitioning to in its destination property. Instead of passing your data to that view controller, you are passing it to a brand new view controller that you create in prepareForSegue (one which is promptly deleted when you leave the function).

You probably want something along the lines of:

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if let graph = segue.destination as? GraphController {
        graph.brain.record = brain.record
    }
}

I typed that without the benefit of a compiler so you may have to tweak it.

Upvotes: 1

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