How to run Python script before each build in Xcode?

Question

I'm trying to run a simple Python script every time I build my app in Xcode. The Python script is called test.py and resides in my project folder as a sibling to my .xcodeproj file.

I think I followed the instructions in the Stack Overflow post Is this possible to run a python script before Xcode doing compiling? but I am receiving the error Shell Script Invocation Error: Command /bin/sh failed with exit code 1

I installed Python 3.5.2, but when I type python -V into Terminal I get Python 2.7.10. However, when I type python3 -V into Terminal I get Python 3.6.0. Typing which python into Terminal returns /usr/bin/python, while typing which python3 into Terminal returns /Library/Frameworks/Python.framework/Versions/3.6/bin/python3.

Following the instructions in Xcode: Running a script before every build that modifies source code directly I also moved the Run Script section in Build Phases to before Compile Sources.

This is what my Run Script section looks like. I have a strong feeling that the fix is annoyingly simple but have been unsuccessful trying to figure out what I am doing wrong / what search terms to use in Google or Stack Overflow.

And of course, let me know what other info I can provide to help debug.

EDIT: I have no preference for which version of Python I use other than that it allows me to run a Python script each time I build. I just installed Python 3.5.2 because I thought it might help.

EDIT 2: Tried deleting Derived Data (even though I am using Xcode 8.2.1) in addition to Clean (Cmd-Shift-K) and Cleaning Build Folder... (Cmd-Shift-Alt-K) and still no luck.

Answer 1

I managed to get this working by using /bin/sh as my shell and python test.py as my script.

Answer 2

In the "Shell" input, try this path: '/Library/Frameworks/Python.framework/Versions/3.5/bin/python3.5'