CODEWITHSUNDEEP
javaconstructorjaxbcreation
Stan Kurilin
Stan Kurilin

Reputation: 15792

JAXB and constructors

I'm starting learning JAXB, so my question can be very silly. Now I have classes and want generate XML Schema. Going after this instruction I get exception

IllegalAnnotationExceptions ... does not have a no-arg default constructor.

Yeah. My classes haven't default no-arg constructors. It's too easy. I have classes with package visible constructors / final methods and off course with arguments. What shall I do - create some specific momemto/builder classes or specify my constructors to JAXB (in what way?) ? Thanks.

Upvotes: 31

Views: 31637

Answers (4)

Rafael M
Rafael M

Reputation: 393

You can use the annotation @XmlType and use factoryMethod / factoryClass attributes in various combinations such as:

@XmlType(factoryMethod="newInstance")
@XmlRootElement
public class PurchaseOrder {
    @XmlElement
    private final String address;
    @XmlElement
    private final Customer customer;

    public PurchaseOrder(String address, Customer customer){
        this.address = address;
        this.customer = customer;
    }

    private PurchaseOrder(){
        this.address = null;
        this.customer = null;
    }
    /** Creates a new instance, will only be used by Jaxb. */
    private static PurchaseOrder newInstance() {
        return new PurchaseOrder();
    }

    public String getAddress() {
        return address;
    }

    public Customer getCustomer() {
        return customer;
    }
}

Surprisingly this works and you get an initialized instance when unmarshalling. You should make note not to call the newInstance method anywhere on your code as it will return an invalid instance.

Upvotes: 16

bdoughan
bdoughan

Reputation: 149017

JAXB can support this case using an XML Adapter. Consider you have the following object with no zero-arg constructor:

package blog.immutable;

public class Customer {

    private final String name;
    private final Address address;

    public Customer(String name, Address address) {
        this.name = name;
        this.address = address;
    }

    public String getName() {
        return name;
    }

    public Address getAddress() {
        return address;
    }

}

You simply need to create a mappable version of this class:

package blog.immutable.adpater;

import javax.xml.bind.annotation.XmlAttribute;
import blog.immutable.Address;

public class AdaptedCustomer {

    private String name;
    private Address address;

    @XmlAttribute
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }

}

And an XML Adapter to convert between them:

package blog.immutable.adpater;

import javax.xml.bind.annotation.adapters.XmlAdapter;
import blog.immutable.Customer;

public class CustomerAdapter extends XmlAdapter<AdaptedCustomer, Customer> {

    @Override
    public Customer unmarshal(AdaptedCustomer adaptedCustomer) throws Exception {
        return new Customer(adaptedCustomer.getName(), adaptedCustomer.getAddress());
    }

    @Override
    public AdaptedCustomer marshal(Customer customer) throws Exception {
        AdaptedCustomer adaptedCustomer = new AdaptedCustomer();
        adaptedCustomer.setName(customer.getName());
        adaptedCustomer.setAddress(customer.getAddress());
        return adaptedCustomer;
    }

}

Then for properties that refer to the Customer class, simply use the @XmlJavaTypeAdapter annotation:

package blog.immutable;

import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;
import blog.immutable.adpater.CustomerAdapter;

@XmlRootElement(name="purchase-order")
public class PurchaseOrder {

    private Customer customer;

    @XmlJavaTypeAdapter(CustomerAdapter.class)
    public Customer getCustomer() {
        return customer;
    }

    public void setCustomer(Customer customer) {
        this.customer = customer;
    }

}

For a more detailed example see:

Upvotes: 42

Valentin Rocher
Valentin Rocher

Reputation: 11669

JAXB re-creates beans from XML in a simple fashion : it creates a new instance of the bean, and then do all the setXXX needed to set the attributes. So, if your bean doesn't have a no-args constructor, JAXB can't create it. As said in other answers, JAXB works better for simple "container" beans, for which no-args constructor isn't really a problem. If you're trying to create beans that need specific initialization, you'll need to do it in the setXXX methods.

Upvotes: 3

Guillaume
Guillaume

Reputation: 5555

You should have a default constructor for JAXB to be able to instantiate your classes. Maybe there is a workaround I don't know though.

JAXB is especially fitted for bean-like classes, permitting to configure objects by calling setters on them.

Upvotes: 5

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