Reputation: 32391
Given a Generic IList
of some type, which contains a number of items, is there any way of 'cropping' this list, so that only the fist x items are preserved, and the rest discarded?
Upvotes: 2
Views: 1783
Reputation: 269498
The existing answers create a new list containing a subset of items from the original list.
If you need to truncate the original list in-place then these are your options:
// if your list is a concrete List<T>
if (yourList.Count > newSize)
{
yourList.RemoveRange(newSize, yourList.Count - newSize);
}
// or, if your list is an IList<T> or IList but *not* a concrete List<T>
while (yourList.Count > newSize)
{
yourList.RemoveAt(yourList.Count - 1);
}
Upvotes: 6
Reputation: 437554
If you need to do it just with the IList<T>
interface, then something like this is the solution:
for (int i = list.Count - 1; i >= numberOfElementsToKeep; --i) {
list.RemoveAt(i);
}
Working backwards from the end of the list here, in order to avoid moving around data which will be deleted in subsequent loop iterations.
Upvotes: 1
Reputation: 26894
you have a very simple way to:
IList<T> list = [...]; //initialize
IList<T> newList = new List<T>(max);
for (i=0; i<max; i++) newList.Add(list[i]);
Note: max MUST be less or equal then list length (otherwise you get IndexOutOfBoundsException
)
Upvotes: 1
Reputation: 35904
If you can use Linq, it's just a matter of doing
// Extraact the first 5 items in myList to newList
var newList = myList.Take(5).ToList();
// You can combine with .Skip() to extract items from the middle
var newList = myList.Skip(2).Take(5).ToList();
Note that the above will create new lists with the 5 elements. If you just want to iterate over the first 5 elements, you don't have to create a new list:
foreach (var oneOfTheFirstFive in myList.Take(5))
// do stuff
Upvotes: 14