CODEWITHSUNDEEP
unixgrep
Gautham Honnavara
Gautham Honnavara

Reputation: 438

How do I count the no of occurrences in a file using grep but with a condition that the occurrences are greater than zero?

I am currently using a grep command:

zgrep -c 'hello' *2017-05-08*

Which counts the total no. of occurrences of the keyword with files having the following name within the **. For example, the output shows like:

log.2017-05-08-15.gz:0
log.2017-05-08-16.gz:0
log.2017-05-08-17.gz:1

It returns a list of files which has the number of occurrences.However, I want only the files which have more than 0 occurrences such as the third file above.

log.2017-05-08-17.gz:1

Can anyone please tell me how could I achieve the desired result. Please let me know if you have any questions

Thanks

Upvotes: 2

Views: 1745

Answers (1)

OnNIX
OnNIX

Reputation: 442

maybe this isn't a good answer, but see if this works:

zgrep -c 'hello' *2017-05-08* | grep -v ":0"

Upvotes: 3

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