CODEWITHSUNDEEP
javaarrays
Manoj Kumar Govindharaj
Manoj Kumar Govindharaj

Reputation: 119

Java converting a group of string to String Array Integer Array

import java.util.List;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.StringTokenizer;
public class sourc {
public static void main(String[] args) {
        String name = null;
        Integer id = null;
        String strings = "one*10*two*11*three*12";
        StringTokenizer st2 = new StringTokenizer(strings, "*");
        while (st2.hasMoreElements()) {
            name = st2.nextElement().toString();
            id = Integer.parseInt(st2.nextElement().toString());
            String[] str = new String[]{name};
            List<String> al = new ArrayList<String>(Arrays.asList(str));
            System.out.println(al);
            ArrayList<Integer> arrli = new ArrayList<Integer>(id);
            arrli.add(id);
            System.out.println(arrli);
        }

}

i have output like

[one]

[10]

[two]

[11]

[three]

[12]

But i need output like

[one,two,three]

[10,11,12]

Upvotes: 4

Views: 389

Answers (4)

Youcef LAIDANI
Youcef LAIDANI

Reputation: 60016

Why you don't use :

public static void main(String[] args) {
    String strings = "one*10*two*11*three*12";
    String[] spl = strings.split("\\*");//split with *
    ArrayList<Integer> arrli = new ArrayList<>();
    List<String> al = new ArrayList<>();
    for (String s : spl) {//loop throw your resutl
        if (s.matches("\\d+")) {//check if your input is int or not
            arrli.add(Integer.parseInt(s));//if int add it to list of ints
        } else {
            al.add(s);//else add it to list of Strings
        }
    }
    System.out.println(al);//output [10, 11, 12]
    System.out.println(arrli);//output [one, two, three]

}

This will help you in case you have two successive ints or String like this :

"one*9*10*two*11*three*four*12"
//--^---^---------^------^

EDIT

now am having my input like "astv*12atthh124ggh*dhr1234sfff123*dgdfg1234*mnaoj" i need to split string and numeric separately

In this case you have to use Patterns for example :

String str = "astv*12atthh124ggh*dhr1234sfff123*dgdfg1234*mnaoj";
Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher(str);
List<String> strings = new ArrayList<>();
List<Integer> nums = new ArrayList<>();
while (m.find()) {
    nums.add(Integer.parseInt(m.group()));
}
p = Pattern.compile("[a-z]+");
m = p.matcher(str);
while (m.find()) {
    strings.add(m.group());
}
System.out.println(nums);
System.out.println(strings);

Outputs

[12, 124, 1234, 123, 1234]
[astv, atthh, ggh, dhr, sfff, dgdfg, mnaoj]

Upvotes: 1

Tim Biegeleisen
Tim Biegeleisen

Reputation: 521979

You don't need a tokenizer here, rather you can just split the string using String#split() with some regex replacement logic.

String input = "one*10*two*11*three*12";
String[] words = input.replaceAll("\\d+\\*?", "")
                      .split("\\*");
String[] nums = input.replaceAll("[^0-9*]+\\*?", "")
                     .split("\\*");

Upvotes: 3

Alexey Soshin
Alexey Soshin

Reputation: 17721

Why not use split?

public static void main(final String[] args) {
    final String strings = "one*10*two*11*three*12";


    final String[] split = strings.split("\\*");

    final List<String> resultStrings = new ArrayList<>();
    final List<String> resultInt = new ArrayList<>();

    for (int i = 0; i < split.length; i++) {
        if (i % 2 == 0) {
            resultInt.add(split[i]);
        } else {
            resultStrings.add(split[i]);
        }
    }

    System.out.println(resultInt);
    System.out.println(resultStrings);
}

Upvotes: 1

Eran
Eran

Reputation: 393936

You should create two Lists outside the loop, and add the elements to them inside the loop:

List<String> names = new ArrayList<String>();
List<Integer> ids = new ArrayList<Integer>();
while (st2.hasMoreElements()) {
    names.add(st2.nextElement().toString());
    ids.add(Integer.parseInt(st2.nextElement().toString()));
}
System.out.println(names);
System.out.println(ids);

Note that this code makes assumptions on the input (even numbers of elements, where the second element of each pair is an integer), and will fail if the input doesn't match these assumptions.

Upvotes: 2

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