CODEWITHSUNDEEP
javascriptphpjqueryajax
AlwaysStudent
AlwaysStudent

Reputation: 1374

How to send data multiple same name input using ajax and php

I am trying to make a poll system for my project like facebook. But I need help in a matter. I use the following JavaScript code to increase the answers for inputs.

$("body").on("click",".createnew", function(){
      $(".inputsl").append("<div class='inputt'><input type='text' name='myanswer' id='createmyanswer' class='myinput' placeholder='Write answer!'></div>");
   });

When you click on the CreateNew button users can prompted to write a new answer. Like this:

<div class="inputsl">
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer" class="myinput"></div>
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer" class="myinput"></div>
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer" class="myinput"></div>
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer" class="myinput"></div>
</div>

So you can see all input name and id is same. It is easy to send one input value. But I want to give the user the right to ask more than one question.

For this I used the following ajax code.

$("body").on("click",".insertp", function(){
       var answers = $("#createmyanswer").val();
       var dataPollAnswers = 'answers=' + answers;
       $.ajax({
           type:'POST',
           url:'/requests/postPollAnswers',
           data: dataPollAnswers,
           cache: false,
           beforeSend: function(){},
           sucess: function(){
               console.log("Success!");
           }   
        });
     });

The last think is php codes for postPollAnswers. I have used the following php codes for sending all created answers.

<?php 
include_once '../inc/inc.php';
if(isset($_POST['answers'])){
    $answers = mysqli_real_escape_string($db, $_POST['answers']);
    if($answers){
foreach($answers as  $setAnswer){
      $insertAnswersfromData = $InSert->Insert_Poll($uid, $setAnswer);
    }
    }
}
?>

I think i have array problem i have searched a solution and tryed many thinks but i can not send multiple answers. I have checked also maybe i need some jquery code like serialize() ect. and tryed but i can not get any result.

Also i am getting this warning:

Warning: Invalid argument supplied for foreach()

Anyone can help me here please ?

Upvotes: 1

Views: 2828

Answers (3)

Milan Chheda
Milan Chheda

Reputation: 8249

Here is working demo for you: 

$("#submit").click(function(){
  var paramsToSend = {};
  var i = 1;
  $("input[name='myanswer[]']").each(function(){
    paramsToSend[i] = $(this).val();
    i++;
  });
  
   $("#dataToSend").html(JSON.stringify(paramsToSend));
   
   $.ajax({
         type: "POST",
         url: 'URL_HERE',
         data: {params:JSON.stringify(paramsToSend)},
         success: function(data) {
          console.log("SUCCESS!!!");
         }
   });
  
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="inputsl">
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer[]" class="myinput"></div>
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer[]" class="myinput"></div>
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer[]" class="myinput"></div>
   <div class="inputt"><input type="text" id="createmyanswer" name="myanswer[]" class="myinput"></div>
</div>
<button id="submit">
Submit
</button>

<div id="dataToSend"></div>

Upvotes: 1

Sagar Arora
Sagar Arora

Reputation: 1783

just take name attribute as array and their id's should be unique:

 var i;

$("body").on("click",".createnew", function(){
      $(".inputsl").append("<div class='inputt'><input type='text' name='myanswer[]' id='createmyanswer'"+i+" class='myinput' placeholder='Write answer!'></div>");
     i++;//no needed if you dont want to use id attribute
   });

Then post as usual using name attribute and you will get array at server side .

Thanks

Upvotes: 1

JYoThI
JYoThI

Reputation: 12085

Just change selector to class name and use serialize

dataPollAnswers = $('.myinput').serialize();

Note : id should be unique

Update 1:

PHP :

foreach($_POST['myanswer'] as $row)
 {             ^^^^^^^^^^
    echo $row;
 }

Note : Input name is myanswer not answer

Update 2:

PHP

    <?php 
    include_once '../inc/inc.php';
    if(isset($_POST['myanswer'])){

            foreach($_POST['myanswer'] as  $setAnswer)
            {
              if(!empty($setAnswer))
              {
              $new_set_ans = mysqli_real_escape_string($db, $setAnswer);
              $insertAnswersfromData = $InSert->Insert_Poll($uid, $new_set_ans);
               }
            }
    }
    ?>

Upvotes: 1

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