Reputation: 79
I was fiddling with C and happen to wrote code below. When I input a string with spaces, program receives all of the input but outputs them as if they were inputted as single words at different times. I thought scanf stopped when first whitespace character is encounterd and ignored the rest. But that seems, is not the case.
I included the output when I enter "inputWithNoSpaces" and "input with spaces", below.
I tried to look into stdin. It receives all the input. But I could not figure out what scanf was doing. I would like to learn what is happening.
Code:
#include <stdio.h>
int main()
{
int i=0;
char word[64]="";
while(1)
{
printf("enter string:");
scanf("%s",word);
i++;
printf("%d:%s\n\n",i,word);
}
return 0;
}
Output:
enter string:inputWithNoSpaces
1:inputWithNoSpaces
enter string:input with spaces
2:input
enter string:3:with
enter string:4:spaces
enter string:
Upvotes: 0
Views: 367
Reputation: 4430
In scanf()
, "%s"
means "skip whitespace characters then read a sequence of non-whitespace characters". So when you give it the input input with spaces
it will return "input"
, "with"
and "spaces"
in three sequential calls. That is the expected behavior. For more information read the manual page.
input with spaces
^^^^^ First scanf("%s", s) reads this
^ Second scanf("%s", s) skips over this whitespace
^^^^ Second scanf("%s", s) reads this
^ Third scanf("%s", s) skips over this whitespace
^^^^^^ Third scanf("%s", s) reads this
Upvotes: 2