CODEWITHSUNDEEP
javascriptphpjqueryajax
user3526204
user3526204

Reputation: 509

js $.post issue

I have the following js code

$('document').ready(function () {
    $('#filterSub').click(function (evt) {
        var data = $('form').serialize();
        var gender = $('#gender').html();

        $.post('data.php', {
            data,
            gender: gender
        }, function (resultp) {
            $('#List').html(resultp);
        });
        $.post('filter.php', {
            data,
            gender: gender
        }, function (result) {
            $('.addFilter').html(result);
        });
        //              alert(gender);

        //return false;
    });
});

I am using 

parse_str($_POST['data'],$_POST);

Which works perfectly fine and I am getting the form variables.

However, I am trying to get the variable 'gender' in my PHP script with 

 $_POST['gender']

in PHP. But it is not getting anything. (setting an alert in the script for 'gender' pops up the correct value)

Also, is there any way I can send both the post queries in one command to the different files? The data being sent is the same.

I am bad at JS so I feel there is an elementary mistake that I am making in the $.post request format.

Any help will be appreciated as I already have spent an entire day on this without any success.

Upvotes: 1

Views: 53

Answers (1)

Barmar
Barmar

Reputation: 782509

The problem is that parse_str($_POST['data'], $_POST); replaces the $_POST array with the result of parsing the data parameter -- any existing entries in the array are lost. So you're losing $_POST['gender'].

You could parse it into a different array:

parse_str($_POST['data'], $data);

or you could extract the gender parameter into a variable before you call parse_str().

$gender = $_POST['gender'];
parse_str($_POST['data'], $data);

Another option is to get rid of the data parameter entirely, just post the serialized fields as separate parameters.

    var data = $('form').serialize();
    var gender = $('#gender').html();
    var params = data + '&gender=' + encodeURIComponent(gender);
    $.post('data.php', params, function (resultp) {
        $('#List').html(resultp);
    });

Upvotes: 3

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