CODEWITHSUNDEEP
javaarraysstringlistreplace
Manoj Kumar Govindharaj
Manoj Kumar Govindharaj

Reputation: 119

Java Converting a group of String by replace the speacial characters

public static void main(String[] args) {
    String str = "astv*12atthh124ggh*dhr1234sfff123*dgdfg1234*mnaoj";
    Pattern p = Pattern.compile("\\d+");
    Matcher m = p.matcher(str);
    List<String> strings = new ArrayList<String>();
    List<Integer> nums = new ArrayList<Integer>();
    while (m.find()) {
        nums.add(Integer.parseInt(m.group()));
    }
    p = Pattern.compile("[a-z]+");
    m = p.matcher(str);
    while (m.find()) {
        strings.add(m.group());
    }
    System.out.println(nums);
    System.out.println(strings);
}

Output:

[12, 124, 1234, 123, 1234]
[astv, atthh, ggh, dhr, sfff, dgdfg, mnaoj]

But i want output like :

[12124, 1234123, 1234]
[astv, atthhggh, dhrsfff, dgdfg, mnaoj]

Upvotes: 2

Views: 96

Answers (3)

Raman Sahasi
Raman Sahasi

Reputation: 31871

To get digit array, you can

  • replace all alphabets with empty string
  • split by asterisk *

- Code

String digitArr[] = str.replaceAll("[A-Za-z]", "").split("\\*");
//output
//12124 1234123 1234

You can repeat same thing for getting alphabet array

String stringArr[] = str.replaceAll("[0-9]", "").split("\\*");
//Output
//astv atthhggh dhrsfff dgdfg mnaoj

DEMO

Upvotes: 1

arcquim
arcquim

Reputation: 1096

To keep original regex logic, you can do as follows:

public static void main(String[] args) {
    String str = "astv*12atthh124ggh*dhr1234sfff123*dgdfg1234*mnaoj";
    List<String> strings = new ArrayList<>();
    List<Integer> nums = new ArrayList<>();
    Pattern digitPattern = Pattern.compile("\\d+");
    Pattern alphaPattern = Pattern.compile("[a-z]+");
    String[] splittedArray = str.split("\\*");
    for (String nextSplittedString : splittedArray) {
        Matcher digitMatcher = digitPattern.matcher(nextSplittedString);
        Matcher alphaMatcher = alphaPattern.matcher(nextSplittedString);
        String nextDigitAsString = "";
        while (digitMatcher.find()) {
            nextDigitAsString += digitMatcher.group();
        }
        if (!nextDigitAsString.isEmpty()) {
            nums.add(Integer.parseInt(nextDigitAsString));
        }

        String nextString = "";
        while (alphaMatcher.find()) {
            nextString += alphaMatcher.group();
        }
        if (!nextString.isEmpty()) {
            strings.add(nextString);
        }
     }
     System.out.println(nums);
     System.out.println(strings);
}

OUTPUT

[12124, 1234123, 1234]
[astv, atthhggh, dhrsfff, dgdfg, mnaoj]

Ideone demo

Upvotes: 1

Youcef LAIDANI
Youcef LAIDANI

Reputation: 60016

You can use split with * then you can work with each element for example :

public static void main(String[] args) {
    String str = "astv*12atthh124ggh*dhr1234sfff123*dgdfg1234*mnaoj";
    String[] spl = str.split("\\*");//[astv, 12atthh124ggh, dhr1234sfff123, dgdfg1234, mnaoj]
    List<String> strings = new ArrayList<>();
    List<Integer> nums = new ArrayList<>();
    for (String s : spl) {

        String tmp = s.replaceAll("\\d+", "");//replace all the digits with empty
        if (!tmp.trim().isEmpty()) {
            strings.add(tmp);
        }

        tmp = s.replaceAll("[a-z]+", "");//replace all the character with empty
        if (!tmp.trim().isEmpty()) {
            nums.add(Integer.parseInt(tmp));
        }
    }

    System.out.println(nums);
    System.out.println(strings);
}

Output

[12124, 1234123, 1234]
[astv, atthhggh, dhrsfff, dgdfg, mnaoj]

Ideone demo

Upvotes: 2

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