Reputation: 309
Suppose we have an array defined like this:
a=[1 2; 3 4; 5 5; 7 9; 1 2];
In Matlab, we could find the maximum values by writing:
[x y] = max(a)
x =
7 9
In Julia, we could use:
a=[1 2; 3 4; 5 5; 7 9; 1 2]
findmax(a,1)
returning:
([7 9],
[4 9])
However, I am interested not only in finding [7 9] for the two columns, but also their relative position within each column, like [4, 4]. Of course, I can write a bit more of coding lines, but can I do it directly with findmax?
Upvotes: 7
Views: 11444
Reputation: 443
This is mentioned in the comments but I figured I'd do a response that's easy to see. I have version 1.0.3, so I don't know what's the earliest version that allows this. But now you can just do
julia> findmax(a) #Returns 2D index of overall maximum value
(9, CartesianIndex(4, 2))
julia> findmax(a[:,1]) #Returns 1D index of max value in column 1
(7, 4)
julia> findmax(a[:,2]) #Returns 1D index of max value in column 2
(9, 4)
Hope this makes things easier.
Upvotes: 2
Reputation: 1434
I've adopted the following function:
indmaxC(x) = cat(1, [indmax(x[:,c]) for c in 1:size(x,2)]...)
A safer version would be:
function indmaxC(x::AbstractArray)
assert(ndims(x)==2)
cat(1, [indmax(x[:,c]) for c in 1:size(x,2)]...)
end
Upvotes: 0
Reputation: 31352
The second matrix returned by findmax
is the linear index of the locations of the maxima over the entire array. You want the position within each column; to get that, you can convert the linear indices into subscripts with ind2sub
. Then the first element of the subscript tuple is your row index.
julia> vals, inds = findmax(a, 1)
(
[7 9],
[4 9])
julia> map(x->ind2sub(a, x), inds)
1×2 Array{Tuple{Int64,Int64},2}:
(4,1) (4,2)
julia> map(x->ind2sub(a, x)[1], inds)
1×2 Array{Int64,2}:
4 4
Upvotes: 8