Reputation: 3403
I checked this question, but the answer (while interesting) basically says "don't use WAR packaging" which is not an option here.
I have a Spring Boot repackaged WAR which uses embedded Tomcat (Spring Boot 1.5.3.RELEASE, embedded Tomcat 8.5.14). The repackaged app runs fine using the mvn spring-boot:run
command but when I try to run it using `java -jar target\mywar.war' I get this:
java.io.FileNotFoundException: file:\C:\work\spring-boot\target\spring-boot-mywar.war!\WEB-INF\classes!\mywar.war (The filename, directory name, or volume label syntax is incorrect)
This is caused when Spring Boot tries to load the context for the "wrapped" war:
Context context = tomcat.addWebapp("/mywar", Thread.currentThread().getContextClassLoader().getResource("mywar.war").getPath());
The actual error takes place inside the embedded Tomcat class:
private URL getWebappConfigFileFromJar(File docBase, String contextName) {
URL result = null;
try (JarFile jar = new JarFile(docBase)) {
JarEntry entry = jar.getJarEntry(Constants.ApplicationContextXml);
if (entry != null) {
result = UriUtil.buildJarUrl(docBase, Constants.ApplicationContextXml);
}
} catch (IOException e) {
Logger.getLogger(getLoggerName(getHost(), contextName)).log(Level.WARNING,
"Unable to determine web application context.xml " + docBase, e);
}
return result;
}
The operation new JarFile(docBase)
throws the FileNotFoundException
.
This works fine when the Maven spring-boot:run
goal is used, so I feel that the basic structure is sound - I think there's some classpath issue or something that's keeping it from working.
Does anyone have any suggestion for duplicating the environment of spring-boot:run
on the command line when using WAR packaging?
Upvotes: 4
Views: 19987
Reputation: 3403
Upon exploring what the actual spring-boot:run goal of the plugin does, it turns out it rebuilds the project and starts the application from the compiled classes in the target/classes
folder. It doesn't appear to use the WAR file at all:
[INFO] --- spring-boot-maven-plugin:1.5.3.RELEASE:run (default-cli) @ spring-boot-app ---
11:58:55.526 [main] INFO app.MyApplication - Beginning run() of MyApplication
2017-05-22 11:58:55.791 DEBUG 4140 --- [ main] .b.l.ClasspathLoggingApplicationListener : Application started with classpath: [file:/C:/work/myapp/target/classes/....[SNIP]
The reason that the WAR wouldn't run is that the internally-contained application WAR file was not being extracted and written to the embedded Tomcat context. Manually extracting the "inside WAR" and writing it to the context location solved the problem:
/**
* Utility method which exports and unpacks the WAR file into the Tomcat context directory
* @param warName
* @param contextPath
* @return
* @throws IOException
* @throws URISyntaxException
*/
private static String exportWar(String warName, String contextPath) throws IOException, URISyntaxException {
log.info("Beginning export WAR");
try {
UnzipUtility unzipUtility = new UnzipUtility();
unzipUtility.unzip(warName, contextPath);
} catch (IOException ex) {
throw ex;
}
return contextPath + warName;
}
Here's the UnzipUtility, based on an example from codejava.net:
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
/**
* This utility extracts files and directories of a standard zip file to
* a destination directory.
* @author www.codejava.net
*
*/
public class UnzipUtility {
/**
* Size of the buffer to read/write data
*/
private static final int BUFFER_SIZE = 4096;
public void unzip(String zipFileName, String destDirectory) throws IOException {
File destDir = new File(destDirectory);
if (!destDir.exists()) {
destDir.mkdir();
}
ZipInputStream zipIn = new ZipInputStream(Thread.currentThread().getContextClassLoader().getResourceAsStream(zipFileName));
ZipEntry entry = zipIn.getNextEntry();
// iterates over entries in the zip file
while (entry != null) {
String filePath = destDirectory + File.separator + entry.getName();
if (!entry.isDirectory()) {
// if the entry is a file, extracts it
ensureParentExists(filePath);
extractFile(zipIn, filePath);
} else {
// if the entry is a directory, make the directory
File dir = new File(filePath);
dir.mkdir();
}
zipIn.closeEntry();
entry = zipIn.getNextEntry();
}
zipIn.close();
}
/**
* Extracts a zip entry (file entry)
* @param zipIn
* @param filePath
* @throws IOException
*/
private void extractFile(ZipInputStream zipIn, String filePath) throws IOException {
BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(filePath));
byte[] bytesIn = new byte[BUFFER_SIZE];
int read = 0;
while ((read = zipIn.read(bytesIn)) != -1) {
bos.write(bytesIn, 0, read);
}
bos.close();
}
private void ensureParentExists(String filePath) {
File parent = new File(filePath).getParentFile();
if ( parent != null && !parent.exists()) {
// parent of parent - recursive
ensureParentExists(parent.getPath());
// make this dir
parent.mkdir();
}
}
}
Upvotes: 1
Reputation: 3883
For spring boot application, you can run with mvn spring-boot:run
, with java -jar thePackage.war
or put the war package in tomcat webapps. Each way should work to run you app.
So I think there is some problem in you project. Make sure you have spring-boot-maven-plugin
in your pom file. Then when you use mvn package
, you should see some log about repackage. If you un-package the war file, you should see some dir like: 'META-INFO' and 'BOOT-INF'.
Upvotes: 3